題干：

CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Being inspired by the entrepreneurial spirit of "HDU CakeMan", he wants to sell some little things to make money. Of course, this is not an easy task.?

As Christmas is around the corner, Boys are busy in choosing christmas presents to send to their girlfriends. It is believed that chain bracelet is a good choice. However, Things are not always so simple, as is known to everyone, girl's fond of the colorful decoration to make bracelet appears vivid and lively, meanwhile they want to display their mature side as college students. after CC understands the girls demands, he intends to sell the chain bracelet called CharmBracelet. The CharmBracelet is made up with colorful pearls to show girls' lively, and the most important thing is that it must be connected by a cyclic chain which means the color of pearls are cyclic connected from the left to right. And the cyclic count must be more than one. If you connect the leftmost pearl and the rightmost pearl of such chain, you can make a CharmBracelet. Just like the pictrue below, this CharmBracelet's cycle is 9 and its cyclic count is 2:?

Now CC has brought in some ordinary bracelet chains, he wants to buy minimum number of pearls to make CharmBracelets so that he can save more money. but when remaking the bracelet, he can only add color pearls to the left end and right end of the chain, that is to say, adding to the middle is forbidden.?
CC is satisfied with his ideas and ask you for help.

Input

The first line of the input is a single integer T ( 0 < T <= 100 ) which means the number of test cases.?
Each test case contains only one line describe the original ordinary chain to be remade. Each character in the string stands for one pearl and there are 26 kinds of pearls being described by 'a' ~'z' characters. The length of the string Len: ( 3 <= Len <= 100000 ).

Output

For each case, you are required to output the minimum count of pearls added to make a CharmBracelet.

Sample Input

3 aaa abca abcde

Sample Output

0 2 5

題目大意：

? 給定一個字符串，問至少還需要在末尾添加多少個字符才能構(gòu)成一個帶有循環(huán)節(jié)的字符串。

解題報告：

? 直接KMP，歸為最小循環(huán)節(jié)問題。

AC代碼：

#include<cstdio> #include<iostream> #include<algorithm> #include<queue> #include<map> #include<vector> #include<set> #include<string> #include<cmath> #include<cstring> #define ll long long #define pb push_back #define pm make_pair #define fi first #define se second using namespace std; const int MAX = 2e5 + 5; char s[MAX]; int Next[MAX]; void getnext() {Next[0] = -1;int k = -1,j = 0;int len = strlen(s); while(j < len) {if(k == -1 || s[k] == s[j]) {k++,j++;Next[j] = k;}else k = Next[k];} } int main() {int t;cin>>t;while(t--) {scanf("%s",s);getnext();int len = strlen(s);int tmplen = strlen(s) - Next[len];if(len != tmplen && len % tmplen == 0) puts("0");else printf("%d\n",tmplen - Next[len]%tmplen);} return 0 ;}

總結(jié)：

? 注意輸出0的時候需要if掉循環(huán)節(jié)長度? 不等于? 字符串長度，，不然就得直接輸出字符串長度（但是可以歸類到else那個情況中）

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