題干：

Given an integer N, your task is to judge whether there exist N points in the plane such that satisfy the following conditions:

1. The distance between any two points is no greater than 1.0.

2. The distance between any point and the origin (0,0) is no greater than 1.0.

3. There are exactly N pairs of the points that their distance is exactly 1.0.

4. The area of the convex hull constituted by these N points is no less than 0.5.

5. The area of the convex hull constituted by these N points is no greater than 0.75.

Input

The first line of the date is an integer T, which is the number of the text cases.

Then T cases follow, each contains an integer N described above.

1 <= T <= 100, 1 <= N <= 100

Output

For each case, output “Yes” if this kind of set of points exists, then output N lines described these N points with its coordinate. Make true that each coordinate of your output should be a real number with AT MOST 6 digits after decimal point.

Your answer will be accepted if your absolute error for each number is no more than 10-4.

Otherwise just output “No”.

See the sample input and output for more details.

Sample Input

3 2 3 5

Sample Output

No No Yes 0.000000 0.525731 -0.500000 0.162460 -0.309017 -0.425325 0.309017 -0.425325 0.500000 0.162460

Hint

This problem is special judge.

題目大意：

給你一個(gè)數(shù)n，讓你找出n個(gè)點(diǎn)，滿(mǎn)足一下關(guān)系：

• 任意兩點(diǎn)的距離不大于1.0
• 所有點(diǎn)到原點(diǎn)的距離不大于1.0
• 恰好有N對(duì)點(diǎn)的距離為1.0
• 由這些點(diǎn)構(gòu)成的n邊形的面積不小于0.5
• 由這些點(diǎn)構(gòu)成的n邊形的面積不大于0.75

解題報(bào)告：

? ? ? ? ? ?因?yàn)辄c(diǎn)可以重復(fù)嘛對(duì)吧所以干脆都輸出那同一個(gè)點(diǎn)好了。。。

AC代碼：

#include<cstdio> #include<cmath> #include<iostream> using namespace std; const int maxn = 35; int main() {int t,n;cin>>t;while(t--) {scanf("%d", &n);if (n <= 3) printf("No\n");else {printf("Yes\n");printf("0 0\n");printf("-0.5 %.6lf\n",sqrt(3.0) / 2);printf("0.5 %.6lf\n",sqrt(3.0) / 2);for (int i = 4; i <= n; i++) {printf("%.6lf %.6lf\n",0.0,1.0);}}}return 0; }

?

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