題2描述：

2

Add Two Numbers

29.10%

Medium

You are given two?non-empty?linked lists representing two non-negative integers. The digits are stored in?reverse order?and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example:

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 Explanation: 342 + 465 = 807.

C語言解法：

/*** Definition for singly-linked list.* struct ListNode {* int val;* struct ListNode *next;* };*/struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2) {struct ListNode *new = (struct ListNode*)malloc(sizeof(struct ListNode));struct ListNode *head = new;int carry = 0;while(l1!=NULL || l2 !=NULL){int d1 = (l1 == NULL) ? 0 :l1->val;int d2 = (l2 == NULL) ? 0 :l2->val;int sum = d1 + d2 + carry;int mod = sum % 10;carry = sum / 10;head->val = mod;if(l1!= NULL)l1 = l1->next;if(l2!= NULL)l2 = l2->next;if(l1 != NULL || l2 != NULL){head->next = (struct ListNode*)malloc(sizeof(struct ListNode));head = head->next;}}head->next = NULL;if(carry==1){head->next = (struct ListNode*)malloc(sizeof(struct ListNode));head->next->val = carry;head->next->next = NULL;}return new;}

遞交結(jié)果：

總結(jié)

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