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reorder-list

發布時間:2023/12/13 编程问答 43 豆豆
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/** ?* Definition for singly-linked list. ?* class ListNode { ?*???? int val; ?*???? ListNode next; ?*???? ListNode(int x) { ?*???????? val = x; ?*???????? next = null; ?*???? } ?* } ?*/ //思路:通過不同的首結點獲取到不同的尾結點,然后拼接 public class Solution { ???public ListNode getLastNode(ListNode head) ????{ ????????ListNode first = head; ????????ListNode fakeLast = head; ????????if (head.next == null) ????????{ ????????????return head; ????????} ????????while (first.next != null) ????????{ ????????????fakeLast = first; ????????????first = first.next; ????????} ????????ListNode last = fakeLast.next; ????????fakeLast.next = null; ????????return last; ????} ????public void reorderList(ListNode head) ????{ ???????if(head==null){ ????????????return; ????????} ????????// 真的首結點 ????????ListNode first = head; ????????// 假的首結點 ????????ListNode fakeFirst = head; ????????while (first.next != null) ????????{ ????????????ListNode last = getLastNode(first); ????????????fakeFirst = first.next; ????????????if (fakeFirst == null) ????????????{ ????????????????first.next = last; ????????????????break; ????????????} ????????????else ????????????{ ????????????????first.next = last; ????????????????last.next = fakeFirst; ????????????????first = fakeFirst; ????????????} ????????} ????} }

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轉載于:https://www.cnblogs.com/qingtianBKY/p/6896754.html

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