sql面试题(学生表_课程表_成绩表_教师表)
原帖鏈接:http://bbs.csdn.net/topics/280002741
表架構(gòu)
Student(S#,Sname,Sage,Ssex) 學(xué)生表?
Course(C#,Cname,T#) 課程表?
SC(S#,C#,score) 成績(jī)表?
Teacher(T#,Tname) 教師表
建表語句?
CREATE TABLE student ( s# INT, sname nvarchar(32), sage INT, ssex nvarchar(8) ) CREATE TABLE course ( c# INT, cname nvarchar(32), t# INT ) CREATE TABLE sc ( s# INT, c# INT, score INT ) CREATE TABLE teacher ( t# INT, tname nvarchar(16) )插入測(cè)試數(shù)據(jù)語句?
insert into Student select 1,N'劉一',18,N'男' union allselect 2,N'錢二',19,N'女' union allselect 3,N'張三',17,N'男' union allselect 4,N'李四',18,N'女' union allselect 5,N'王五',17,N'男' union allselect 6,N'趙六',19,N'女' insert into Teacher select 1,N'葉平' union allselect 2,N'賀高' union allselect 3,N'楊艷' union allselect 4,N'周磊'insert into Course select 1,N'語文',1 union allselect 2,N'數(shù)學(xué)',2 union allselect 3,N'英語',3 union allselect 4,N'物理',4insert into SC select 1,1,56 union all select 1,2,78 union all select 1,3,67 union all select 1,4,58 union all select 2,1,79 union all select 2,2,81 union all select 2,3,92 union all select 2,4,68 union all select 3,1,91 union all select 3,2,47 union all select 3,3,88 union all select 3,4,56 union all select 4,2,88 union all select 4,3,90 union all select 4,4,93 union all select 5,1,46 union all select 5,3,78 union all select 5,4,53 union all select 6,1,35 union all select 6,2,68 union all select 6,4,71問題
問題: 1、查詢“001”課程比“002”課程成績(jī)高的所有學(xué)生的學(xué)號(hào); select a.S# from (select s#,score from SC where C#='001') a,(select s#,score from SC where C#='002') b where a.score>b.score and a.s#=b.s#; 2、查詢平均成績(jī)大于60分的同學(xué)的學(xué)號(hào)和平均成績(jī); select S#,avg(score) from sc group by S# having avg(score) >60; 3、查詢所有同學(xué)的學(xué)號(hào)、姓名、選課數(shù)、總成績(jī); select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname 4、查詢姓“李”的老師的個(gè)數(shù); select count(distinct(Tname)) from Teacher where Tname like '李%'; 5、查詢沒學(xué)過“葉平”老師課的同學(xué)的學(xué)號(hào)、姓名; select Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平'); 6、查詢學(xué)過“001”并且也學(xué)過編號(hào)“002”課程的同學(xué)的學(xué)號(hào)、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002'); 7、查詢學(xué)過“葉平”老師所教的所有課的同學(xué)的學(xué)號(hào)、姓名; select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平')); 8、查詢課程編號(hào)“002”的成績(jī)比課程編號(hào)“001”課程低的所有同學(xué)的學(xué)號(hào)、姓名; Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2 from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score; 9、查詢所有課程成績(jī)小于60分的同學(xué)的學(xué)號(hào)、姓名; select S#,Sname from Student where S# not in (select S.S# from Student AS S,SC where S.S#=SC.S# and score>60); 10、查詢沒有學(xué)全所有課的同學(xué)的學(xué)號(hào)、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course); 11、查詢至少有一門課與學(xué)號(hào)為“1001”的同學(xué)所學(xué)相同的同學(xué)的學(xué)號(hào)和姓名; select distinct S#,Sname from Student,SC where?Student.S#=SC.S# and SC.C# in (select C# from SC where S#='1001'); 12、查詢至少學(xué)過學(xué)號(hào)為“001”同學(xué)所有一門課的其他同學(xué)學(xué)號(hào)和姓名; select distinct SC.S#,Sname from Student,SC where Student.S#=SC.S# and C# in (select C# from SC where S#='001'); 13、把“SC”表中“葉平”老師教的課的成績(jī)都更改為此課程的平均成績(jī); update SC set score=(select avg(SC_2.score) from SC SC_2 where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平'); 14、查詢和“1002”號(hào)的同學(xué)學(xué)習(xí)的課程完全相同的其他同學(xué)學(xué)號(hào)和姓名; select S# from SC where C# in (select C# from SC where S#='1002') group by S# having count(*)=(select count(*) from SC where S#='1002'); 15、刪除學(xué)習(xí)“葉平”老師課的SC表記錄; Delect SC from course ,Teacher where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平'; 16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號(hào)“003”課程的同學(xué)學(xué)號(hào)、2、 號(hào)課的平均成績(jī); Insert SC select S#,'002',(Select avg(score) from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002'); 17、按平均成績(jī)從高到低顯示所有學(xué)生的“數(shù)據(jù)庫(kù)”、“企業(yè)管理”、“英語”三門的課程成績(jī),按如下形式顯示: 學(xué)生ID,,數(shù)據(jù)庫(kù),企業(yè)管理,英語,有效課程數(shù),有效平均分 SELECT S# as 學(xué)生ID ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 數(shù)據(jù)庫(kù) ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業(yè)管理 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語 ,COUNT(*) AS 有效課程數(shù), AVG(t.score) AS 平均成績(jī) FROM SC AS t GROUP BY S# ORDER BY avg(t.score) 18、查詢各科成績(jī)最高和最低的分:以如下形式顯示:課程ID,最高分,最低分 SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分 FROM SC L ,SC AS R WHERE L.C# = R.C# and L.score = (SELECT MAX(IL.score) FROM SC AS IL,Student AS IM WHERE L.C# = IL.C# and IM.S#=IL.S# GROUP BY IL.C#) AND R.Score = (SELECT MIN(IR.score) FROM SC AS IR WHERE R.C# = IR.C# GROUP BY IR.C# );自己寫的:select c# ,max(score)as 最高分 ,min(score) as 最低分 from dbo.sc ?group by c# 19、按各科平均成績(jī)從低到高和及格率的百分?jǐn)?shù)從高到低順序 SELECT t.C# AS 課程號(hào),max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績(jī) ,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分?jǐn)?shù) FROM SC T,Course where t.C#=course.C# GROUP BY t.C# ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC 20、查詢?nèi)缦抡n程平均成績(jī)和及格率的百分?jǐn)?shù)(用"1行"顯示): 企業(yè)管理(001),馬克思(002),OO&UML (003),數(shù)據(jù)庫(kù)(004) SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業(yè)管理平均分 ,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業(yè)管理及格百分?jǐn)?shù) ,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分 ,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分?jǐn)?shù) ,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分 ,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分?jǐn)?shù) ,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 數(shù)據(jù)庫(kù)平均分 ,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 數(shù)據(jù)庫(kù)及格百分?jǐn)?shù) FROM SC 21、查詢不同老師所教不同課程平均分從高到低顯示 SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績(jī) FROM SC AS T,Course AS C ,Teacher AS Z where T.C#=C.C# and C.T#=Z.T# GROUP BY C.C# ORDER BY AVG(Score) DESC 22、查詢?nèi)缦抡n程成績(jī)第 3 名到第 6 名的學(xué)生成績(jī)單:企業(yè)管理(001),馬克思(002),UML (003),數(shù)據(jù)庫(kù)(004) [學(xué)生ID],[學(xué)生姓名],企業(yè)管理,馬克思,UML,數(shù)據(jù)庫(kù),平均成績(jī) SELECT DISTINCT top 3 SC.S# As 學(xué)生學(xué)號(hào), Student.Sname AS 學(xué)生姓名 , T1.score AS 企業(yè)管理, T2.score AS 馬克思, T3.score AS UML, T4.score AS 數(shù)據(jù)庫(kù), ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分 FROM Student,SC LEFT JOIN SC AS T1 ON SC.S# = T1.S# AND T1.C# = '001' LEFT JOIN SC AS T2 ON SC.S# = T2.S# AND T2.C# = '002' LEFT JOIN SC AS T3 ON SC.S# = T3.S# AND T3.C# = '003' LEFT JOIN SC AS T4 ON SC.S# = T4.S# AND T4.C# = '004' WHERE student.S#=SC.S# and ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) NOT IN (SELECT DISTINCT TOP 15 WITH TIES ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) FROM sc LEFT JOIN sc AS T1 ON sc.S# = T1.S# AND T1.C# = 'k1' LEFT JOIN sc AS T2 ON sc.S# = T2.S# AND T2.C# = 'k2' LEFT JOIN sc AS T3 ON sc.S# = T3.S# AND T3.C# = 'k3' LEFT JOIN sc AS T4 ON sc.S# = T4.S# AND T4.C# = 'k4' ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC); 23、統(tǒng)計(jì)列印各科成績(jī),各分?jǐn)?shù)段人數(shù):課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60] SELECT SC.C# as 課程ID, Cname as 課程名稱 ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85] ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70] ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60] ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -] FROM SC,Course where SC.C#=Course.C# GROUP BY SC.C#,Cname; 24、查詢學(xué)生平均成績(jī)及其名次 SELECT 1+(SELECT COUNT( distinct 平均成績(jī)) FROM (SELECT S#,AVG(score) AS 平均成績(jī) FROM SC GROUP BY S# ) AS T1 WHERE 平均成績(jī) > T2.平均成績(jī)) as 名次, S# as 學(xué)生學(xué)號(hào),平均成績(jī) FROM (SELECT S#,AVG(score) 平均成績(jī) FROM SC GROUP BY S# ) AS T2 ORDER BY 平均成績(jī) desc; 25、查詢各科成績(jī)前三名的記錄:(不考慮成績(jī)并列情況) SELECT t1.S# as 學(xué)生ID,t1.C# as 課程ID,Score as 分?jǐn)?shù) FROM SC t1 WHERE score IN (SELECT TOP 3 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 26、查詢每門課程被選修的學(xué)生數(shù) select c#,count(S#) from sc group by C#; 27、查詢出只選修了一門課程的全部學(xué)生的學(xué)號(hào)和姓名 select SC.S#,Student.Sname,count(C#) AS 選課數(shù) from SC ,Student where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1; 28、查詢男生、女生人數(shù) Select count(Ssex) as 男生人數(shù) from Student group by Ssex having Ssex='男'; Select count(Ssex) as 女生人數(shù) from Student group by Ssex having Ssex='女'; 29、查詢姓“張”的學(xué)生名單 SELECT Sname FROM Student WHERE Sname like '張%'; 30、查詢同名同性學(xué)生名單,并統(tǒng)計(jì)同名人數(shù) select Sname,count(*) from Student group by Sname having count(*)>1;; 31、1981年出生的學(xué)生名單(注:Student表中Sage列的類型是datetime) select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age from student where CONVERT(char(11),DATEPART(year,Sage))='1981'; 32、查詢每門課程的平均成績(jī),結(jié)果按平均成績(jī)升序排列,平均成績(jī)相同時(shí),按課程號(hào)降序排列 Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ; 33、查詢平均成績(jī)大于85的所有學(xué)生的學(xué)號(hào)、姓名和平均成績(jī) select Sname,SC.S# ,avg(score) from Student,SC where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85; 34、查詢課程名稱為“數(shù)據(jù)庫(kù)”,且分?jǐn)?shù)低于60的學(xué)生姓名和分?jǐn)?shù) Select Sname,isnull(score,0) from Student,SC,Course where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='數(shù)據(jù)庫(kù)'and score <60; 35、查詢所有學(xué)生的選課情況; SELECT SC.S#,SC.C#,Sname,Cname FROM SC,Student,Course where SC.S#=Student.S# and SC.C#=Course.C# ; 36、查詢?nèi)魏我婚T課程成績(jī)?cè)?0分以上的姓名、課程名稱和分?jǐn)?shù); SELECT distinct student.S#,student.Sname,SC.C#,SC.score FROM student,Sc WHERE SC.score>=70 AND SC.S#=student.S#; 37、查詢不及格的課程,并按課程號(hào)從大到小排列 select c# from sc where scor e <60 order by C# ; 38、查詢課程編號(hào)為003且課程成績(jī)?cè)?0分以上的學(xué)生的學(xué)號(hào)和姓名; select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003'; 39、求選了課程的學(xué)生人數(shù) select count(*) from sc; 40、查詢選修“葉平”老師所授課程的學(xué)生中,成績(jī)最高的學(xué)生姓名及其成績(jī) select Student.Sname,score from Student,SC,Course C,Teacher where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='葉平' and SC.score=(select max(score)from SC where C#=C.C# ); 41、查詢各個(gè)課程及相應(yīng)的選修人數(shù) select count(*) from sc group by C#; 42、查詢不同課程成績(jī)相同的學(xué)生的學(xué)號(hào)、課程號(hào)、學(xué)生成績(jī) select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ; 43、查詢每門功成績(jī)最好的前兩名 SELECT t1.S# as 學(xué)生ID,t1.C# as 課程ID,Score as 分?jǐn)?shù) FROM SC t1 WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 44、統(tǒng)計(jì)每門課程的學(xué)生選修人數(shù)(超過10人的課程才統(tǒng)計(jì))。要求輸出課程號(hào)和選修人數(shù),查詢結(jié)果按人數(shù)降序排列,查詢結(jié)果按人數(shù)降序排列,若人數(shù)相同,按課程號(hào)升序排列 select C# as 課程號(hào),count(*) as 人數(shù) from sc group by C# order by count(*) desc,c# 45、檢索至少選修兩門課程的學(xué)生學(xué)號(hào) select S# from sc group by s# having count(*) > = 2 46、查詢?nèi)繉W(xué)生都選修的課程的課程號(hào)和課程名 select C#,Cname from Course where C# in (select c# from sc group by c#) 47、查詢沒學(xué)過“葉平”老師講授的任一門課程的學(xué)生姓名 select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='葉平'); 48、查詢兩門以上不及格課程的同學(xué)的學(xué)號(hào)及其平均成績(jī) select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#; 49、檢索“004”課程分?jǐn)?shù)小于60,按分?jǐn)?shù)降序排列的同學(xué)學(xué)號(hào) select S# from SC where C#='004'and score <60 order by score desc; 50、刪除“002”同學(xué)的“001”課程的成績(jī) delete from Sc where S#='001'and C#='001';
問題描述:
本題用到下面三個(gè)關(guān)系表:
CARD 借書卡。 CNO 卡號(hào),NAME 姓名,CLASS 班級(jí)
BOOKS 圖書。 BNO 書號(hào),BNAME 書名,AUTHOR 作者,PRICE 單價(jià),QUANTITY 庫(kù)存冊(cè)數(shù)
BORROW 借書記錄。 CNO 借書卡號(hào),BNO 書號(hào),RDATE 還書日期
備注:限定每人每種書只能借一本;庫(kù)存冊(cè)數(shù)隨借書、還書而改變。
要求實(shí)現(xiàn)如下15個(gè)處理:
1. 寫出建立BORROW表的SQL語句,要求定義主碼完整性約束和引用完整性約束 --實(shí)現(xiàn)代碼: CREATE TABLE BORROW(CNO int FOREIGN KEY REFERENCES CARD(CNO),BNO int FOREIGN KEY REFERENCES BOOKS(BNO),RDATE datetime,PRIMARY KEY(CNO,BNO)) 2. 找出借書超過5本的讀者,輸出借書卡號(hào)及所借圖書冊(cè)數(shù) --實(shí)現(xiàn)代碼: SELECT CNO,借圖書冊(cè)數(shù)=COUNT(*) FROM BORROW GROUP BY CNO HAVING COUNT(*)>53. 查詢借閱了"水滸"一書的讀者,輸出姓名及班級(jí) --實(shí)現(xiàn)代碼: SELECT * FROM CARD c WHERE EXISTS(SELECT * FROM BORROW a,BOOKS b WHERE a.BNO=b.BNOAND b.BNAME=N'水滸'AND a.CNO=c.CNO) 4. 查詢過期未還圖書,輸出借閱者(卡號(hào))、書號(hào)及還書日期 --實(shí)現(xiàn)代碼: SELECT * FROM BORROW WHERE RDATE<GETDATE() 5. 查詢書名包括"網(wǎng)絡(luò)"關(guān)鍵詞的圖書,輸出書號(hào)、書名、作者 --實(shí)現(xiàn)代碼: SELECT BNO,BNAME,AUTHOR FROM BOOKS WHERE BNAME LIKE N'%網(wǎng)絡(luò)%' 6. 查詢現(xiàn)有圖書中價(jià)格最高的圖書,輸出書名及作者 --實(shí)現(xiàn)代碼: SELECT BNO,BNAME,AUTHOR FROM BOOKS WHERE PRICE=(SELECT MAX(PRICE) FROM BOOKS) 7. 查詢當(dāng)前借了"計(jì)算方法"但沒有借"計(jì)算方法習(xí)題集"的讀者,輸出其借書卡號(hào),并按卡號(hào)降序排序輸出 --實(shí)現(xiàn)代碼: SELECT a.CNO FROM BORROW a,BOOKS b WHERE a.BNO=b.BNO AND b.BNAME=N'計(jì)算方法'AND NOT EXISTS(SELECT * FROM BORROW aa,BOOKS bbWHERE aa.BNO=bb.BNOAND bb.BNAME=N'計(jì)算方法習(xí)題集'AND aa.CNO=a.CNO) ORDER BY a.CNO DESC 8. 將"C01"班同學(xué)所借圖書的還期都延長(zhǎng)一周 --實(shí)現(xiàn)代碼: UPDATE b SET RDATE=DATEADD(Day,7,b.RDATE) FROM CARD a,BORROW b WHERE a.CNO=b.CNOAND a.CLASS=N'C01' 9. 從BOOKS表中刪除當(dāng)前無人借閱的圖書記錄 --實(shí)現(xiàn)代碼: DELETE A FROM BOOKS a WHERE NOT EXISTS(SELECT * FROM BORROWWHERE BNO=a.BNO) 10. 如果經(jīng)常按書名查詢圖書信息,請(qǐng)建立合適的索引 --實(shí)現(xiàn)代碼: CREATE CLUSTERED INDEX IDX_BOOKS_BNAME ON BOOKS(BNAME)11. 在BORROW表上建立一個(gè)觸發(fā)器,完成如下功能:如果讀者借閱的書名是"數(shù)據(jù)庫(kù)技術(shù)及應(yīng)用",就將該讀者的借閱記錄保存在BORROW_SAVE表中(注ORROW_SAVE表結(jié)構(gòu)同BORROW表) --實(shí)現(xiàn)代碼: CREATE TRIGGER TR_SAVE ON BORROW FOR INSERT,UPDATE AS IF @@ROWCOUNT>0 INSERT BORROW_SAVE SELECT i.* FROM INSERTED i,BOOKS b WHERE i.BNO=b.BNOAND b.BNAME=N'數(shù)據(jù)庫(kù)技術(shù)及應(yīng)用' 12. 建立一個(gè)視圖,顯示"力01"班學(xué)生的借書信息(只要求顯示姓名和書名) --實(shí)現(xiàn)代碼: CREATE VIEW V_VIEW AS SELECT a.NAME,b.BNAME FROM BORROW ab,CARD a,BOOKS b WHERE ab.CNO=a.CNOAND ab.BNO=b.BNOAND a.CLASS=N'力01'13. 查詢當(dāng)前同時(shí)借有"計(jì)算方法"和"組合數(shù)學(xué)"兩本書的讀者,輸出其借書卡號(hào),并按卡號(hào)升序排序輸出 --實(shí)現(xiàn)代碼: SELECT a.CNO FROM BORROW a,BOOKS b WHERE a.BNO=b.BNOAND b.BNAME IN(N'計(jì)算方法',N'組合數(shù)學(xué)') GROUP BY a.CNO HAVING COUNT(*)=2 ORDER BY a.CNO DESC 14. 假定在建BOOKS表時(shí)沒有定義主碼,寫出為BOOKS表追加定義主碼的語句 --實(shí)現(xiàn)代碼: ALTER TABLE BOOKS ADD PRIMARY KEY(BNO) 15.1 將NAME最大列寬增加到10個(gè)字符(假定原為6個(gè)字符) --實(shí)現(xiàn)代碼: ALTER TABLE CARD ALTER COLUMN NAME varchar(10) 15.2 為該表增加1列NAME(系名),可變長(zhǎng),最大20個(gè)字符 --實(shí)現(xiàn)代碼: ALTER TABLE CARD ADD 系名 varchar(20)問題描述: 為管理崗位業(yè)務(wù)培訓(xùn)信息,建立3個(gè)表:
S (S#,SN,SD,SA) S#,SN,SD,SA 分別代表學(xué)號(hào)、學(xué)員姓名、所屬單位、學(xué)員年齡
C (C#,CN ) C#,CN 分別代表課程編號(hào)、課程名稱
SC ( S#,C#,G ) S#,C#,G 分別代表學(xué)號(hào)、所選修的課程編號(hào)、學(xué)習(xí)成績(jī)
要求實(shí)現(xiàn)如下5個(gè)處理:
1. 使用標(biāo)準(zhǔn)SQL嵌套語句查詢選修課程名稱為’稅收基礎(chǔ)’的學(xué)員學(xué)號(hào)和姓名 --實(shí)現(xiàn)代碼: SELECT SN,SD FROM S WHERE [S#] IN(SELECT [S#] FROM C,SCWHERE C.[C#]=SC.[C#]AND CN=N'稅收基礎(chǔ)')2. 使用標(biāo)準(zhǔn)SQL嵌套語句查詢選修課程編號(hào)為’C2’的學(xué)員姓名和所屬單位 --實(shí)現(xiàn)代碼: SELECT S.SN,S.SD FROM S,SC WHERE S.[S#]=SC.[S#]AND SC.[C#]='C2'3. 使用標(biāo)準(zhǔn)SQL嵌套語句查詢不選修課程編號(hào)為’C5’的學(xué)員姓名和所屬單位 --實(shí)現(xiàn)代碼: SELECT SN,SD FROM S WHERE [S#] NOT IN(SELECT [S#] FROM SC WHERE [C#]='C5')4. 使用標(biāo)準(zhǔn)SQL嵌套語句查詢選修全部課程的學(xué)員姓名和所屬單位 --實(shí)現(xiàn)代碼: SELECT SN,SD FROM S WHERE [S#] IN(SELECT [S#] FROM SC RIGHT JOIN C ON SC.[C#]=C.[C#]GROUP BY [S#]HAVING COUNT(*)=COUNT(DISTINCT [S#]))5. 查詢選修了課程的學(xué)員人數(shù) --實(shí)現(xiàn)代碼: SELECT 學(xué)員人數(shù)=COUNT(DISTINCT [S#]) FROM SC6. 查詢選修課程超過5門的學(xué)員學(xué)號(hào)和所屬單位 --實(shí)現(xiàn)代碼: SELECT SN,SD FROM S WHERE [S#] IN(SELECT [S#] FROM SC GROUP BY [S#]HAVING COUNT(DISTINCT [C#])>5)?
?
轉(zhuǎn)載于:https://www.cnblogs.com/qixuejia/p/3637735.html
總結(jié)
以上是生活随笔為你收集整理的sql面试题(学生表_课程表_成绩表_教师表)的全部?jī)?nèi)容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: 3.1 详细讲解直线段工具 [Illus
- 下一篇: 044. 使用 CDN 实现应用的缓存和