I use python 2.6

>>> hex(-199703103)

'-0xbe73a3f'

>>> hex(199703103)

'0xbe73a3f'

Positive and negative value are the same?

When I use calc, the value is FFFFFFFFF418C5C1.

解決方案

Python's integers can grow arbitrarily large. In order to compute the raw two's-complement the way you want it, you would need to specify the desired bit width. Your example shows -199703103 in 64-bit two's complement, but it just as well could have been 32-bit or 128-bit, resulting in a different number of 0xf's at the start.

hex() doesn't do that. I suggest the following as an alternative:

def tohex(val, nbits):

return hex((val + (1 << nbits)) % (1 << nbits))

print tohex(-199703103, 64)

print tohex(199703103, 64)

This prints out:

0xfffffffff418c5c1L

0xbe73a3fL

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