一、?? ?列?? ?轉?? ?行

create table STU_ROW2COL

(

id????? VARCHAR2(10),

intname VARCHAR2(10),

subject VARCHAR2(20),

grade?? NUMBER

)

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('1', 'ZORRO', '語文', 70);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('2', 'ZORRO', '數學', 80);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('3', 'ZORRO', '英語', 75);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('4', 'SEKER', '語文', 65);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('5', 'SEKER', '數學', 75);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('6', 'SEKER', '英語', 60);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('7', 'BLUES', '語文', 60);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('8', 'BLUES', '數學', 90);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('9', 'PG', '數學', 80);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('10', 'PG', '英語', 90);

SQL>? select t.* from stu_row2col t ;

ID???????? INTNAME??? SUBJECT?????????????????? GRADE

---------- ---------- -------------------- ----------

11???????? ZORRO????? 語文???????????????????????? 77

1????????? ZORRO????? 語文???????????????????????? 70

2????????? ZORRO????? 數學???????????????????????? 80

3????????? ZORRO????? 英語???????????????????????? 75

4????????? SEKER????? 語文???????????????????????? 65

5????????? SEKER????? 數學???????????????????????? 75

6????????? SEKER????? 英語???????????????????????? 60

7????????? BLUES????? 語文???????????????????????? 60

8????????? BLUES????? 數學???????????????????????? 90

9????????? PG???????? 數學???????????????????????? 80

10???????? PG???????? 英語???????????????????????? 90

想要實現行專列， 就是輸出結果是這樣的：

SQL>? select * from ( select t.intname,t.subject,t.grade from stu_row2col t)

pivot(sum(grade) for subject in ('語文' 語文,'數學' 數學,'英語' 英語))? ;

INTNAME??????????? 語文???????? 數學???????? 英語

---------- ---------- ---------- ----------

SEKER????????????? 65???????? 75???????? 60

BLUES????????????? 60???????? 90

PG??????????????????????????? 80???????? 90

ZORRO???????????? 147???????? 80???????? 75

二、?? ?行?? ?轉?? ?列

創建一個視圖：

create or replace view stu_col2row as

select "INTNAME","語文","數學","英語" from ( select t.intname,t.subject,t.grade from stu_row2col t) pivot(sum(grade) for subject in ('語文' 語文,'數學' 數學,'英語' 英語));

SQL>? select INTNAME 姓名,km 科目, fs 分數 from stu_col2row unpivot(fs for km in(語文,數學,英語));

姓名?????? 科目???????? 分數

---------- ---- ----------

SEKER????? 語文???????? 65

SEKER????? 數學???????? 75

SEKER????? 英語???????? 60

BLUES????? 語文???????? 60

BLUES????? 數學???????? 90

PG???????? 數學???????? 80

PG???????? 英語???????? 90

ZORRO????? 語文???????? 70

ZORRO????? 數學???????? 80

ZORRO????? 英語???????? 75

總結

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