String.contains()如果此字符串包含，此方法返回true，否則返回false import java.io.*;public class Main {public static void main(String[] args) throws IOException {BufferedReader br = new BufferedReader(new InputStreamReader(System.in));PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));int n = Integer.parseInt(br.readLine());String[] real = br.readLine().split(" "); // 實數double sum = 0; // 合法實數的和int k = 0; // 合法實數的個數for (int i = 0; i < n; ++i) {try {double x = Double.parseDouble(real[i]);// 解析成double型不合法拋異常int width = 0; // 小數部分位數if (real[i].contains(".")) { // 是小數width = real[i].length() - real[i].indexOf('.') - 1;// 小數位數}if (x < -1000 || x > 1000 || width > 2) {// 超范圍或小數部分過長throw new NumberFormatException();}sum += x;++k;} catch (NumberFormatException e) { // 處理異常，輸出信息System.out.println("ERROR: " + real[i] + " is not a legal number");}}if (k==0) { // 無合法實數System.out.println("The average of 0 numbers is Undefined");} else if (k==1) { // 只有1個合法實數System.out.printf("The average of 1 number is %.2f", sum);// 單數無s字符} else { // 多個合法實數System.out.printf("The average of %d numbers is %.2f", k, sum / k);}} }

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