假設你得到了四個任意順序的坐標,可以通過我編的程序獲得該矩形的長寬,角度和中心點

import cv2 import mathclass Point(object): # 坐標類def __init__(self, xParam=0.0, yParam=0.0):self.x = xParamself.y = yParamdef distance(self, pt):xDiff = self.x - pt.xyDiff = self.y - pt.yreturn math.sqrt(xDiff ** 2 + yDiff ** 2)def show(self):print("(%.2f, %.2f)" % (self.x, self.y))def substract(self, pt): # 減法生成向量newPt = Point()xNew = self.x - pt.xyNew = self.y - pt.yreturn Point(xNew, yNew)def add(self, pt): # 加法生成中心點newPt = Point()xNew = (self.x + pt.x) / 2yNew = (self.y + pt.y) / 2return Point(xNew, yNew)# 求取兩個向量間的余弦值 def cosVector(p1, p2):result1 = p1.x * p2.x + p1.y * p2.y result2 = p1.x ** 2 + p1.y ** 2 result3 = p2.x ** 2 + p2.y ** 2 return result1 / ((result2 * result3) ** 0.5)# 有向矩形的四個頂點輸入順序任意時，返回旋轉角度，w，h def points_to_grasps(p, num=4, is_pos=True): # 默認矩形框的w大于hres = []p = sorted(p, key=lambda Points: Points.x) d12 = p[0].distance(p[1])d13 = p[0].distance(p[2])center_O = p[0].add(p[3]) vector_OB = Point(1, 0) w = min(d12, d13)h = max(d12, d13)if d12 > d13: point_A = p[1].add(p[3])else:if p[1].y < p[2].y: point_A = p[2].add(p[3])else: point_A = p[0].add(p[1])vector_OA = point_A.substract(center_O) if is_pos: cos_AOB = cosVector(vector_OA, vector_OB)box_class = cos_to_class(cos_AOB)else:box_class = 0res.append(str(center_O.x))res.append(str(center_O.y))res.append(str(w))res.append(str(h))res.append(str(box_class))return res

轉載請附上鏈接

總結

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