/*需求：統計這個大字符串中出現幾次java統計大串中小串出現的次數舉例：在字符串"woaijavawozhenaijavawozhendeaijavawozhendehenaijavaxinbuxinwoaijava"中java出現了5次javawozhenaijavawozhendeaijavawozhendehenaijavaxinbuxinwoaijavajavawozhendeaijavawozhendehenaijavaxinbuxinwoaijavaA:定義統計變量count = 0;B:先獲取一次java在大串中出現的寫次數,如果是-1,則不存在,返回統計變量,如果索引值不是-1,就返回統計變量++C:把剛才的索引+小串的長度，作為起始位置截取原始大串,得到一個新的字符串,重新賦值給大串D:回到B重復即可*/ public class StringInquiry {public static void main(String[] args) {String maxString = "woaijavawozhenaijavawozhendeaijavawozhendehenaijavaxinbuxinwoaijava";String minString = "java";int count = getConut(maxString, minString);System.out.println("java在大串中出現了：" + count + "次");}public static int getConut(String maxString, String minString) {int count = 0;//先在大串中查一下小串的位置int index = maxString.indexOf(minString); //4while (index != -1) {count++;int startIndex = index + minString.length(); //4+4maxString = maxString.substring(startIndex); //wozhenaijavawozhendeaijavawozhendehenaijavaxinbuxinwoaijavagunindex = maxString.indexOf(minString); //8}return count;} }

代碼優化后：?

public class StringInquiry {public static void main(String[] args) {String maxString = "woaijavawozhenaijavawozhendeaijavawozhendehenaijavaxinbuxinwoaijava";String minString = "java";int count = getConut(maxString, minString);System.out.println("java在大串中出現了：" + count + "次");}public static int getConut(String maxString, String minString) {int count = 0;while (maxString.contains(minString)) {count++;maxString = maxString.substring(maxString.indexOf(minString) + minString.length());}return count;} }

總結

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