我們可以實(shí)現(xiàn)ISerializable接口來(lái)自定義串行化行為。這個(gè)接口只有一個(gè)方法GetObjectData。這個(gè)方法用于將對(duì)類對(duì)象進(jìn)行序列化所需的數(shù)據(jù)填進(jìn)SerializationInfo對(duì)象。你使用的格式化器（比如BinaryFormatter）將構(gòu)造SerializationInfo對(duì)象，然后在序列化時(shí)調(diào)用GetObjectData。因此，你需要實(shí)現(xiàn)GetObjectData，讓它添加你從類中選擇的值，并且映射到你選擇的字符串名。注意，如果類的父類也實(shí)現(xiàn)ISerializable，那么應(yīng)該調(diào)用GetObjectData的父類實(shí)現(xiàn)。
給出例子：
using?System;
using?System.IO;
using?System.Runtime.Serialization;
using?System.Runtime.Serialization.Formatters.Binary;
[Serializable]
public?class?Insect?:?ISerializable
{
????private?string?name;
????private?int?id;
????public?Insect(string?name,?int?id)
????{
????????this.name?=?name;
????????this.id?=?id;
????}
????public?override?string?ToString()
????{
????????return?String.Format("{0}:{1}",?name,?id);
????}
????public?Insect(){}
????
????public?virtual?void?GetObjectData(SerializationInfo?s,?StreamingContext?c)
????{
????????s.AddValue("CommonName",?name);
????????s.AddValue("ID#",?id);
????}
????private?Insect(SerializationInfo?s,?StreamingContext?c)
????{
????????name?=?s.GetString("CommonName");
????????id?=?s.GetInt32("ID#");
????}
}

class?ImpISerialApp
{
????static?void?Main(string[]?args)
????{
????????Insect?i?=?new?Insect("Meadow?Brown",?12);
????????Stream?s?=?File.Create("Insect.bin");
????????BinaryFormatter?b?=?new?BinaryFormatter();
????????b.Serialize(s,?i);
????????s.Seek(0,?SeekOrigin.Begin);
????????Insect?j?=?(Insect)b.Deserialize(s);
????????s.Close();
????????Console.WriteLine(j);
????}
}
Insect.bin包含以下信息：
DISerializable, Version=0.0.0.0, Culture=neutral, PublicKeyToken=null Insect
CommonName ID# Meadow Brown

轉(zhuǎn)載于:https://www.cnblogs.com/wdxinren/archive/2004/10/23/55826.html

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