bzoj 1096 斜率優化水題，（?閉著眼做）

/**************************************************************Problem: 1096User: BriMonLanguage: C++Result: AcceptedTime:2576 msMemory:55980 kb ****************************************************************/#include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; #define maxn 1000010 #define int long longint n, x[maxn], p[maxn], c[maxn]; int sum[maxn], s[maxn];int f[maxn]; inline int G(int i) {return x[i]; }inline int X(int i) {return sum[i]; }inline int D(int i) {return c[i] - s[i] + x[i] * sum[i]; }inline int Y(int i) {return f[i] + s[i]; }inline double slope(int a, int b) {return ((double)(Y(b) - Y(a)) / (double)(X(b) - X(a))); }int q[maxn], l, r;signed main() {cin >> n;for (int i = 1; i <= n; i++){scanf("%lld%lld%lld", &x[i], &p[i], &c[i]);sum[i] = sum[i-1] + p[i];s[i] = s[i-1] + x[i] * p[i];f[i] = 0x7f7f7f7f;}for (int i = 1; i <= n; i++){while (l < r && slope(q[l], q[l+1]) < G(i)) l++;int j = q[l];f[i] = Y(j) - G(i) * X(j) + D(i);while(l < r && slope(q[r-1], q[r]) > slope(q[r-1], i)) r--;q[++r] = i;}cout << f[n];return 0; } zZhBr

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bzoj 1003 DP加SPFA調了一下午（我太弱了）

/**************************************************************Problem: 1003User: BriMonLanguage: C++Result: AcceptedTime:44 msMemory:1384 kb ****************************************************************/#include <iostream> #include <cstdio> #include <algorithm> #include <queue> #include <cstring> using namespace std;int n, m, c, e, d;struct edge {int nxt;int to;int val; }ed[4000];int head[25], cnt;void add(int x, int y, int z) {cnt++;ed[cnt].nxt = head[x];ed[cnt].to = y;ed[cnt].val = z;head[x] = cnt; }int f[101][101], dp[101];bool cant[25][105];bool flag[21];int dis[21]; bool ex[21]; queue <int> q; int SPFA() {memset(dis, 0x3f, sizeof dis);memset(ex, 0, sizeof ex);dis[1] = 0;ex[1] = 1;while(!q.empty()) q.pop();q.push(1);while(!q.empty()){int t = q.front();q.pop();ex[t] = 0;for (int i = head[t] ; i ; i = ed[i].nxt){int to = ed[i].to, v = ed[i].val;if(dis[to] > dis[t] + v and !flag[to]){dis[to] = dis[t] + v;if(!ex[to]){ex[to] = 1;q.push(to);}}}} // printf("%d\n", dis[m]);return dis[m]; }int main() {cin >> n >> m >> c >> e;for (int i = 1 ; i <= e ; i ++){int x, y, z;scanf("%d%d%d", &x, &y, &z);add(x, y, z);add(y, x, z);}cin >> d;for (int i = 1 ; i <= d ; i ++){int x, y, z;scanf("%d%d%d", &x, &y, &z);for (int j = y ; j <= z ; j ++){cant[x][j] = 1;}}for (int i = 1 ; i <= n ; i++){for (int j = i ; j <= n ; j++){memset(flag, 0, sizeof flag);for (int k = 1 ; k <= m ; k ++){for(int l = i ; l <= j ; l ++){flag[k] |= cant[k][l];}}f[i][j] = SPFA();// cout << f[i][j] << endl; }}memset(dp, 0x7f, sizeof dp);for (int i = 1 ; i <= n ; i ++){for (int j = i ; j <= n ; j ++){if(f[i][j] < 0x3f3f3f3f) f[i][j] *= (j - i + 1);}}for (int i = 1 ; i <= n ; i ++) dp[i] = f[1][i];for (int i = 2 ; i <= n ; i++){for (int j = 1 ; j < i ; j ++){dp[i] = min(dp[i], dp[j] + f[j+1][i] + c);}}cout << dp[n];return 0; } zZhBr

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Luogu 2756 作為機房里唯一一個還不會網絡流的蒟蒻，對著這道模板題瑟瑟發抖

#include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <queue> using namespace std;int n, m;struct edge {int nxt;int to;int flow; }ed[5005];int head[201], cnt = 1;void add(int x, int y, int z) {cnt++, ed[cnt].nxt = head[x], ed[cnt].to = y, ed[cnt].flow = z, head[x] = cnt;cnt++, ed[cnt].nxt = head[y], ed[cnt].to = x, ed[cnt].flow = 0, head[y] = cnt; }int S = 0, T = n + 1;int d[205];queue <int> q;bool bfs(){memset(d, 0, sizeof d);while(!q.empty()) q.pop();q.push(S);d[S] = 1;while (!q.empty()){int x = q.front();q.pop();for (int i = head[x] ; i ; i = ed[i].nxt){int to = ed[i].to;if(!ed[i].flow || d[to]) continue;q.push(to);d[to] = d[x] + 1;if (to == T) return 1;}}return 0; }int Dinic(int x, int flow){if(x == T) return flow;int rest = flow, k;for (int i = head[x] ; i and rest; i = ed[i].nxt){int to = ed[i].to;if(ed[i].flow and d[to] == d[x] + 1){k = Dinic(to, min(rest, ed[i].flow));if (!k) d[to] = 0;ed[i].flow -= k;ed[i ^ 1].flow += k;rest -= k;}}return flow - rest; }int ans;int main() {cin >> m >> n;int x, y;T = n + 1;for (int i = 1 ; i <= m ; i ++) add(S, i, 1);for (int i = m + 1 ; i <= n ; i++) add(i, T, 1);while(scanf("%d%d", &x, &y) != EOF and x != -1 and y != -1){add(x, y, 1);}int flow = 0;while (bfs()){while (flow = Dinic(S, 1 << 29)) ans += flow;}if(!ans){puts("No Solution");return 0;}cout << ans << endl;for (int i = 2 ; i <= cnt ; i += 2){if(ed[i].to != S and ed[i ^ 1].to != S and ed[i].to != T and ed[i ^ 1].to != S and ed[i ^ 1].flow != 0){printf("%d %d\n", ed[i ^ 1].to, ed[i].to);}}return 0;} zZhBr

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bzoj 1022 nim裸題， 雖然不會博弈

/**************************************************************Problem: 1022User: BriMonLanguage: C++Result: AcceptedTime:100 msMemory:1288 kb ****************************************************************/#include <iostream> #include <cstdio> #include <cstring> using namespace std;int T; int ans, n, sum;int main() {cin >> T;while (T--){cin >> n;ans = 0;sum = 0;for (int i = 1 ; i <= n ; i ++){int a;scanf("%d", &a);ans ^= a;sum += a;}if(sum == n){if (sum & 1) puts("Brother");else puts("John");continue;}if (ans){puts("John");}else puts("Brother");}return 0; } zZhBr

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轉載于:https://www.cnblogs.com/BriMon/p/8992444.html

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