如果我們想要外鍵的邏輯，像這樣

FOREIGN KEY COmments(issue_id)

REFERENCES Bugs(issue_id) OR FeatureRequests(issue_id)

例：

CREATE TABLE Issues (

issue_id int PRIMARY KEY,

status VARCHAR(20)

);

CREATE TABLE Comments (

comment_id int PRIMARY KEY,

issue_type VARCHAR(20), -- "Bugs" or "FeatureRequests"

issue_id BIGINT UNSIGNED NOT NULL,

comment TEXT

);

CREATE TABLE Bugs (

issue_id int PRIMARY KEY,

severity VARCHAR(20),

FOREIGN KEY (issue_id) REFERENCES Issues(issue_id)

);

CREATE TABLE FeatureRequests (

issue_id int PRIMARY KEY,

sponsor VARCHAR(50),

FOREIGN KEY (issue_id) REFERENCES Issues(issue_id)

);

INSERT INTO Issues VALUES(1,'ON'),(2,'ON'),(3,'OFF'),(6,'OFF'),(8,'ON');

INSERT INTO Comments VALUES(1,'Bugs',1,'A'),(2,'Bugs',3,'B'),(3,'Bugs',1,'C'),(4,'Bugs',3,'D'),(5 ,'FeatureRequests',8,'L'),

(6,'FeatureRequests',6,'W'),(7,'FeatureRequests',1,'ZX');

INSERT INTO Bugs VALUES(1,'severity_1'),(3,'severity_for_3');

INSERT INTO FeatureRequests VALUES(2,'sponsor_2_'),(8,'sponsor_for_8'),(1,'sponsor_for_1')

選擇：

MariaDB [test]> SELECT * FROM Comments JOIN FeatureRequests ON Comments.issue_i

d = FeatureRequests.issue_id AND Comments.issue_type= 'FeatureRequests';

MariaDB [test]> SELECT * FROM Comments JOIN Bugs ON Comments.issue_id = Bugs.is

sue_id AND Comments.issue_type= 'Bugs';

+------------+------------+----------+---------+----------+----------------+

| comment_id | issue_type | issue_id | comment | issue_id | severity |

+------------+------------+----------+---------+----------+----------------+

| 1 | Bugs | 1 | A | 1 | severity_1 |

| 2 | Bugs | 3 | B | 3 | severity_for_3 |

| 3 | Bugs | 1 | C | 1 | severity_1 |

| 4 | Bugs | 3 | D | 3 | severity_for_3 |

+------------+------------+----------+---------+----------+----------------+

4 rows in set (0.00 sec)

總結

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