I have a local version of Python 3.4.1 and I can run python -m pip install, but I'm unable to find the pip binary to run pip install. What's the difference between these two?

解決方案

2014

They do exactly the same thing. In fact, the docs for distributing Python modules were just updated to suggest using python -m pip instead of the pip executable, because it's easier to tell which version of python is going to be used to actually run pip that way.

Here's some more concrete "proof", beyond just trusting my word and the bug report I linked :)

If you take a look at the pip executable script, it's just doing this:

from pkg_resources import load_entry_point

load_entry_point('pip==1.5.4', 'console_scripts', 'pip')()

It's calling load_entry_point, which returns a function, and then executing that function. The entry point it's using is called 'console_scripts'. If you look at the entry_points.txt file for pip (/usr/lib/python2.7/dist-packages/pip-1.5.4.egg-info/entry_points.txt on my Ubuntu machine), you'll see this:

[console_scripts]

pip = pip:main

pip2.7 = pip:main

pip2 = pip:main

So the entry point returned is the main function in the pip module.

When you run python -m pip, you're executing the __main__.py script inside the pip package. That looks like this:

import sys

from .runner import run

if __name__ == '__main__':

exit = run()

if exit:

sys.exit(exit)

And the runner.run function looks like this:

def run():

base = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))

## FIXME: this is kind of crude; if we could create a fake pip

## module, then exec into it and update pip.__path__ properly, we

## wouldn't have to update sys.path:

sys.path.insert(0, base)

import pip

return pip.main()

As you can see, it's just calling the pip.main function, too. So both commands end up calling the same main function in pip/__init__.py.

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