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java版数据结构解迷宫问题_C语言数据结构之迷宫问题

發布時間:2023/12/19 编程问答 25 豆豆
生活随笔 收集整理的這篇文章主要介紹了 java版数据结构解迷宫问题_C语言数据结构之迷宫问题 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

本文實例為大家分享了數據結構c語言版迷宮問題棧實現的具體代碼,供大家參考,具體內容如下

程序主要參考自嚴蔚敏老師的數據結構c語言版,在書中程序的大體框架下進行了完善。關于迷宮問題的思路可查閱原書。

#include

using namespace std;

#define MAXSIZE 10

typedef int Status;

typedef struct{

int x;

int y;

}Postype;

typedef struct{

int ord;

Postype seat;

int dir;

}SElemType;//棧的元素類型

typedef struct{

//SElemType data[MAXSIZE];

SElemType* top;

SElemType* base;

}Stack;//棧的結構類型

typedef struct{

char arr[MAXSIZE][MAXSIZE];

}MAZETYPE;//迷宮結構體

MAZETYPE maze;

void InitMaze()

{

maze.arr[0][0] = maze.arr[0][1] = maze.arr[0][2] = maze.arr[0][3] = maze.arr[0][4] = maze.arr[0][5] = maze.arr[0][6] = maze.arr[0][7] = maze.arr[0][8] = maze.arr[0][9] = '1';

maze.arr[1][0] = maze.arr[1][3] = maze.arr[1][7] = maze.arr[1][9] = '1';

maze.arr[1][1] = maze.arr[1][2] = maze.arr[1][4] = maze.arr[1][5] = maze.arr[1][6] = maze.arr[1][8] = '0';

maze.arr[2][0] = maze.arr[2][3] = maze.arr[2][7] = maze.arr[2][9] = '1';

maze.arr[2][1] = maze.arr[2][2] = maze.arr[2][4] = maze.arr[2][5] = maze.arr[2][6] = maze.arr[2][8] = '0';

maze.arr[3][0] = maze.arr[3][5] = maze.arr[3][6] = maze.arr[3][9] = '1';

maze.arr[3][1] = maze.arr[3][2] = maze.arr[3][3] = maze.arr[3][4] = maze.arr[3][7] = maze.arr[3][8] = '0';

maze.arr[4][0] = maze.arr[4][2] = maze.arr[4][3] = maze.arr[4][4] = maze.arr[4][9] = '1';

maze.arr[4][1] = maze.arr[4][5] = maze.arr[4][6] = maze.arr[4][7] = maze.arr[4][8] = '0';

maze.arr[5][0] = maze.arr[5][4] = maze.arr[5][9] = '1';

maze.arr[5][1] = maze.arr[5][2] = maze.arr[5][3] = maze.arr[5][5] = maze.arr[5][6] = maze.arr[5][7] = maze.arr[5][8] = '0';

maze.arr[6][0] = maze.arr[6][2] = maze.arr[6][6] = maze.arr[6][9] = '1';

maze.arr[6][1] = maze.arr[6][3] = maze.arr[6][4] = maze.arr[6][5] = maze.arr[6][7] = maze.arr[6][8] = '0';

maze.arr[7][0] = maze.arr[7][2] = maze.arr[7][3] = maze.arr[7][4] = maze.arr[7][6] = maze.arr[7][9] = '1';

maze.arr[7][1] = maze.arr[7][5] = maze.arr[7][7] = maze.arr[7][8] = '0';

maze.arr[8][0] = maze.arr[8][1] = maze.arr[8][9] = '0';

maze.arr[8][2] = maze.arr[8][3] = maze.arr[8][4] = maze.arr[8][5] = maze.arr[8][6] = maze.arr[8][7] = maze.arr[8][8] = '0';

maze.arr[9][0] = maze.arr[9][1] = maze.arr[9][2] = maze.arr[9][3] = maze.arr[9][4] = maze.arr[9][5] = maze.arr[9][6] = maze.arr[9][7] = maze.arr[9][8] = maze.arr[9][9] = '1';

}

Status initStack(Stack &s)

{

s.base = (SElemType*)malloc(MAXSIZE*sizeof(SElemType));

if (!s.base) return 0;

s.top = s.base;

return 1;

}

void Push(Stack &s, SElemType e)

{

*s.top++ = e;

}

void Pop(Stack &s, SElemType &e)

{

e = *--s.top;

}

Status StackEmpty(Stack &s)

{

if (s.top == s.base) return 1;

else return 0;

}

Status Pass(Postype curpos)

{

if (maze.arr[curpos.x][curpos.y] == '0')

return 1;

else return 0;

}

void Foot(Postype curpos)

{

maze.arr[curpos.x][curpos.y] = '*';

}

void MarkPrint(Postype curpos)

{

maze.arr[curpos.x][curpos.y] = '!';

}

Status StructCmp(Postype a, Postype b)

{

if (a.x = b.x&&a.y == b.y) return 1;

else return 0;

}

//下一個位置

Postype NextPos(Postype CurPos, int Dir)

{

Postype ReturnPos;

switch (Dir)

{

case 1:

ReturnPos.x = CurPos.x;

ReturnPos.y = CurPos.y + 1;

break;

case 2:

ReturnPos.x = CurPos.x + 1;

ReturnPos.y = CurPos.y;

break;

case 3:

ReturnPos.x = CurPos.x;

ReturnPos.y = CurPos.y - 1;

break;

case 4:

ReturnPos.x = CurPos.x - 1;

ReturnPos.y = CurPos.y;

break;

}

return ReturnPos;

}

Status MazePath(Postype start, Postype end)

{

Stack s;

SElemType e;

initStack(s);

Postype curpos = start;

int curstep = 1;

do{

if (Pass(curpos))

{

Foot(curpos);

e = { curstep, curpos, 1 };

Push(s, e);

if (StructCmp(curpos, end)) return 1;

curpos = NextPos(curpos, 1);

curstep++;

}

else

{

if (!StackEmpty(s))

{

Pop(s, e);

while (e.dir ==4 &&!StackEmpty(s))

{

MarkPrint(e.seat); Pop(s, e);

}

if (e.dir < 4 && !StackEmpty(s))

{

e.dir++;

Push(s, e);

curpos = NextPos(e.seat, e.dir);

}

}

}

} while (!StackEmpty(s));

return 0;

}

int main()

{

InitMaze();

Postype s, e;

s.x = s.y = 1;

e.x = e.y = 8;

if (MazePath(s, e))

printf("迷宮成功解密!\n");

else

printf("解密失敗\n");

for (int i = 0; i < 10; i++)

{

for (int j = 0; j < 10; j++)

{

printf("%c ", maze.arr[i][j]);

}

printf("\n");

}

cout << "-=================================" << endl;

for (int i = 0; i < 10; i++)

{

for (int j = 0; j < 10; j++)

{

if (maze.arr[i][j] == '*' || maze.arr[i][j] == '!')

printf("%c ", maze.arr[i][j]);

else cout << " ";

}

printf("\n");

}

}

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