用ABAP實現下圖的第五種整數相加算法：

實現代碼：

REPORT zint.PARAMETERS: a TYPE int4 OBLIGATORY DEFAULT 100,b TYPE int4 OBLIGATORY DEFAULT 100.DATA: threshold TYPE int4.FORM add USING a TYPE int4 b TYPE int4 CHANGING cv_result TYPE int4.DATA: n TYPE int4 VALUE 0,c TYPE int4 VALUE 0.DATA: i TYPE int4 VALUE 1.DATA: boolean_a TYPE abap_bool,boolean_b TYPE abap_bool,_a TYPE int4,_b TYPE int4,aa TYPE int4,bb TYPE int4.DATA(wrapper_one) = zcl_integer=>value_of( 1 ).DATA(wrapper_c) = zcl_integer=>value_of( c ).aa = a.bb = b.WHILE i < threshold.DATA(wrapper_a) = zcl_integer=>value_of( aa ).DATA(wrapper_b) = zcl_integer=>value_of( bb ).boolean_a = boolc( wrapper_a->and( wrapper_one )->get_raw_value( ) EQ 1 ).boolean_b = boolc( wrapper_b->and( wrapper_one )->get_raw_value( ) EQ 1 )._a = COND int4( WHEN boolean_a EQ abap_true THEN 1 ELSE 0 )._b = COND int4( WHEN boolean_b EQ abap_true THEN 1 ELSE 0 ).wrapper_a = zcl_integer=>value_of( _a ).wrapper_b = zcl_integer=>value_of( _b ).wrapper_c = zcl_integer=>value_of( c ).DATA(_n_wrapper) = wrapper_a->xor( wrapper_b )->xor( wrapper_c ).DATA(b_or_c) = wrapper_b->or( wrapper_c ).DATA(b_and_c) = wrapper_b->and( wrapper_c ).DATA(_c_wrapper) = wrapper_a->and( b_or_c )->or( b_and_c ).c = _c_wrapper->get_raw_value( ).DATA(_n_i0_wrapper) = zcl_integer=>value_of( COND int4( WHEN _n_wrapper->get_raw_value( ) > 0 THEN i ELSE 0 ) ).DATA(wrapper_n) = zcl_integer=>value_of( n ).n = wrapper_n->or( _n_i0_wrapper )->get_raw_value( ).wrapper_a = zcl_integer=>value_of( aa ).aa = wrapper_a->shift_right( )->get_raw_value( ).wrapper_b = zcl_integer=>value_of( bb ).bb = wrapper_b->shift_right( )->get_raw_value( ).cv_result = n.DATA(wrapper_i) = zcl_integer=>value_of( i ).wrapper_i->shift_left( ).i = wrapper_i->get_raw_value( ).ENDWHILE.ENDFORM.START-OF-SELECTION.DATA: i TYPE int4.threshold = ipow( base = 2 exp = 30 ).PERFORM add USING a b CHANGING i.WRITE: / i.

算法描述參考我的SCN博客 Just for fun – Implement a + b using pure bitwise operation in ABAP

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