BBS中父模塊縮進，子模塊歸屬父模塊的實現方式

板塊顯示順序問題

在tbl_board表中增加一個顯示順序字段 order

alter table tbl_board
add ( order_num number(3) );

update tbl_board set order_num = 20 where boardname = '.NET技術';

update tbl_board set order_num = 21 where boardname = 'C#語言';
update tbl_board set order_num = 22 where boardname = 'WinForms';
update tbl_board set order_num = 23 where boardname = 'ADO.NET ';
update tbl_board set order_num = 24 where boardname = 'ASP.NET ';

update tbl_board set order_num = 10 where boardname = 'Java技術';

update tbl_board set order_num = 11 where boardname = 'Java基礎';
update tbl_board set order_num = 12 where boardname = 'JSP技術 ';
update tbl_board set order_num = 13 where boardname = 'Servlet技術 ';
update tbl_board set order_num = 14 where boardname = 'Eclipse應用';

update tbl_board set order_num = 30 where boardname = '數據庫技術';

update tbl_board set order_num = 31 where boardname = 'Oracle ';
update tbl_board set order_num = 32 where boardname = 'SQL Server';

update tbl_board set order_num = 40 where boardname = '娛樂';
update tbl_board set order_num = 41 where boardname = '灌水樂園';

commit;

-------------------------------------------------------------------------

清單查詢sql

select b.boardname , nvl(t1.topic_count , 0) as topic_count , t2.title , t2.uname , t2.publishtime
from tbl_board? b
left join ( select boardid , count(*) as topic_count from tbl_topic group by boardid ) t1 on b.boardid = t1.boardid
left join (
?select boardid ,title , uname , publishtime
?from tbl_topic t21
?join tbl_user u on t21.userid = u.userid
?where publishtime = (
??select max(publishtime)
??from tbl_topic t22
??where t22.boardid = t21.boardid
?)
) t2? on b.boardid = t2.boardid
order by b.order_num;

?

posted on 2012-09-24 20:16 moonfans 閱讀(...) 評論(...) 編輯 收藏

轉載于:https://www.cnblogs.com/moonfans/archive/2012/09/24/2700613.html

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