根據(jù)Unix時(shí)間戳計(jì)算時(shí)間，不分年月大小，每月三十天，每年按360天計(jì)算。開(kāi)始時(shí)間1970/01/01 00:00:00,輸入秒數(shù)，顯示時(shí)間

思路一：進(jìn)位，60秒進(jìn)1分鐘，60分進(jìn)1小時(shí)，24小時(shí)進(jìn)1天，30天進(jìn)1月，12月進(jìn)1年，依次建立循環(huán) while (second > 60){second -= 60;minute += 1;if (minute == 60){minute = 0;hour += 1;if (hour == 24){hour = 0;day += 1;if (day == 31){day = 1;month += 1;if (month == 13){month = 1;year += 1;}}}}}

完整代碼：

string CalculationDate(long long second) {int year = 1970, month = 1, day = 1;int hour = 0, minute = 0;// 考慮使用計(jì)數(shù)思想，秒合法，則算出了最終時(shí)間while (second > 60){second -= 60;minute += 1;if (minute == 60){minute = 0;hour += 1;if (hour == 24){hour = 0;day += 1;if (day == 31){day = 1;month += 1;if (month == 13){month = 1;year += 1;}}}}}char buff[] = "1970/01/01 00:00:10";sprintf(buff,"%d/%02d/%02d %02d:%02d:%02d", year, month, day, hour, minute, second);return buff; } 思路二：取整，一年多少秒，一月多少秒，以此類推，依次取年、月、日.... long long minuteSecond = 60;long long hourSecond = 60*minuteSecond;long long daySecond = 24*hourSecond;long long monthSecond = 30*daySecond;long long yearSecond = 12*monthSecond;

完整代碼：

string CalculationDate_OP(long long second) {int year = 1970, month = 1, day = 1;int hour = 0, minute = 0;// 考慮直接去整的思想long long minuteSecond = 60;long long hourSecond = 60*minuteSecond;long long daySecond = 24*hourSecond;long long monthSecond = 30*daySecond;long long yearSecond = 12*monthSecond;if (second > yearSecond){int x = second/yearSecond;year += x;second -= x*yearSecond;}if (second > monthSecond){int x = second/monthSecond;month += x;second -= x*monthSecond;}if (second > daySecond){int x = second/daySecond;day += x;second -= x*daySecond;}if (second > hourSecond){int x = second/hourSecond;hour += x;second -= x*hourSecond;}if (second > minuteSecond){int x = second/minuteSecond;minute += x;second -= x*minuteSecond;}char buff[] = "1970/01/01 00:00:10";sprintf(buff,"%d/%02d/%02d %02d:%02d:%02d", year, month, day, hour, minute, second);return buff; }

測(cè)試：

void test() {cout<< CalculationDate(10)<<endl;cout<< CalculationDate(12345678)<<endl;cout<< CalculationDate_OP(10)<<endl;cout<< CalculationDate_OP(12345678)<<endl; }

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