自己的代碼：

# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = Noneclass Solution:def allNode(self,root):listNode=[]if Not root:return ListNodecheckResult=checkNode(root)if checkResult is not None:listNode.append(checkResult)if not root.left:self.allNode(root.left) if not root.left:self.allNode(root.right)def checkNode(self,root):if not root.left and not root.right :return root.valreturn Nonedef leafSimilar(self, root1, root2):""":type root1: TreeNode:type root2: TreeNode:rtype: bool"""node1=allNode(root1)node2=allNode(root2)if node1==node2:return Truereturn False

主要問題：思維有些混亂，在使用遞歸的時候，先把針對單個結點的返回想好，再使用遞歸。

優秀代碼：

https://blog.csdn.net/fuxuemingzhu/article/details/81748617

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先序遍歷：

# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = Noneclass Solution:def leafSimilar(self, root1, root2):""":type root1: TreeNode:type root2: TreeNode:rtype: bool"""return self.getLeafs(root1) == self.getLeafs(root2)def getLeafs(self, root):res = []if not root:return resif not root.left and not root.right:return [root.val]res.extend(self.getLeafs(root.left))res.extend(self.getLeafs(root.right))return res

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修改之后的代碼：

# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = Noneclass Solution:def leafSimilar(self, root1, root2):node1=self.allNode(root1)node2=self.allNode(root2)if node1==node2:return Truereturn Falsedef allNode(self,root):listNode=[]if not root:return ListNodeif not root.left and not root.right :return [root.val]listNode.extend(self.allNode(root.left))listNode.extend(self.allNode(root.right))return listNode

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轉載于:https://www.cnblogs.com/captain-dl/p/10154334.html

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