linux 时区 0900是哪,c＃-解析DateTime的时区为PST / CEST / UTC /
c＃-解析DateTime的時區為PST / CEST / UTC /
我正在嘗試解析類似于以下內容的國際日期時間字符串：
24-okt-08 21:09:06 CEST
到目前為止，我有類似的東西：
CultureInfo culture = CultureInfo.CreateSpecificCulture("nl-BE");
DateTime dt = DateTime.ParseExact("24-okt-08 21:09:06 CEST",
"dd-MMM-yy HH:mm:ss ...", culture);
問題是我應該對格式字符串中的“ ...”使用什么？ 查看“自定義日期和時間格式字符串” MSDN頁面似乎沒有以PST / CEST / GMT / UTC格式列出用于解析時區的格式字符串。
6個解決方案
32 votes
AFAIK無法識別時區縮寫。 但是，如果用時區偏移量代替縮寫，那就可以了。 例如。：
DateTime dt1 = DateTime.ParseExact("24-okt-08 21:09:06 CEST".Replace("CEST", "+2"), "dd-MMM-yy HH:mm:ss z", culture);
DateTime dt2 = DateTime.ParseExact("24-okt-08 21:09:06 CEST".Replace("CEST", "+02"), "dd-MMM-yy HH:mm:ss zz", culture);
DateTime dt3 = DateTime.ParseExact("24-okt-08 21:09:06 CEST".Replace("CEST", "+02:00"), "dd-MMM-yy HH:mm:ss zzz", culture);
Panos answered 2020-07-24T18:23:05Z
22 votes
快速的答案是，您無法做到。
這就是為什么
有一個世界時區的權威數據庫，您可以從IANA那里獲取。
問題是3或4個字母的縮寫與IANA時區具有多對一關聯。 例如"CST"的含義不同，這取決于您的文化，所處的世界以及應用程序的上下文。
AMT "Armenia Time" Asia UTC + 4 hours
AMT "Amazon Time" South America UTC - 4 hours
如果您真的想解決這個問題，建議您使用Noda Time代表您的"CST"s。 您必須編寫一些代碼將縮寫詞轉換為標準IANA時區。
我們無法為您完成此操作，這取決于您應用程序的上下文。
另一個很好的例子是"CST"。
CST "China Standard Time" Asia UTC + 8 hours
CST "Central Standard Time" Central America UTC - 6 hours
CST "Cuba Standard Time" Caribbean UTC - 5 hours
CST "Central Standard Time" North America UTC - 6 hours
Jodrell answered 2020-07-24T18:23:52Z
9 votes
如果您決定走搜索與替換路線的縮寫字典(我這樣做了)。
Dictionary _timeZones = new Dictionary() {
{"ACDT", "+1030"},
{"ACST", "+0930"},
{"ADT", "-0300"},
{"AEDT", "+1100"},
{"AEST", "+1000"},
{"AHDT", "-0900"},
{"AHST", "-1000"},
{"AST", "-0400"},
{"AT", "-0200"},
{"AWDT", "+0900"},
{"AWST", "+0800"},
{"BAT", "+0300"},
{"BDST", "+0200"},
{"BET", "-1100"},
{"BST", "-0300"},
{"BT", "+0300"},
{"BZT2", "-0300"},
{"CADT", "+1030"},
{"CAST", "+0930"},
{"CAT", "-1000"},
{"CCT", "+0800"},
{"CDT", "-0500"},
{"CED", "+0200"},
{"CET", "+0100"},
{"CEST", "+0200"},
{"CST", "-0600"},
{"EAST", "+1000"},
{"EDT", "-0400"},
{"EED", "+0300"},
{"EET", "+0200"},
{"EEST", "+0300"},
{"EST", "-0500"},
{"FST", "+0200"},
{"FWT", "+0100"},
{"GMT", "GMT"},
{"GST", "+1000"},
{"HDT", "-0900"},
{"HST", "-1000"},
{"IDLE", "+1200"},
{"IDLW", "-1200"},
{"IST", "+0530"},
{"IT", "+0330"},
{"JST", "+0900"},
{"JT", "+0700"},
{"MDT", "-0600"},
{"MED", "+0200"},
{"MET", "+0100"},
{"MEST", "+0200"},
{"MEWT", "+0100"},
{"MST", "-0700"},
{"MT", "+0800"},
{"NDT", "-0230"},
{"NFT", "-0330"},
{"NT", "-1100"},
{"NST", "+0630"},
{"NZ", "+1100"},
{"NZST", "+1200"},
{"NZDT", "+1300"},
{"NZT", "+1200"},
{"PDT", "-0700"},
{"PST", "-0800"},
{"ROK", "+0900"},
{"SAD", "+1000"},
{"SAST", "+0900"},
{"SAT", "+0900"},
{"SDT", "+1000"},
{"SST", "+0200"},
{"SWT", "+0100"},
{"USZ3", "+0400"},
{"USZ4", "+0500"},
{"USZ5", "+0600"},
{"USZ6", "+0700"},
{"UT", "-0000"},
{"UTC", "-0000"},
{"UZ10", "+1100"},
{"WAT", "-0100"},
{"WET", "-0000"},
{"WST", "+0800"},
{"YDT", "-0800"},
{"YST", "-0900"},
{"ZP4", "+0400"},
{"ZP5", "+0500"},
{"ZP6", "+0600"}
};
Jussi Palo answered 2020-07-24T18:24:12Z
3 votes
我有兩個答案，因為我不確定您要問什么。
1)我看到您正在使用CultureInfo，所以如果您只想格式化特定于文化的日期和時間，我將日期/時間和時區分開，在日期/時間上應用文化方法并附加時區。 如果“ CEST”因不同的文化而不同，則您必須通過列出所有選項來更改它(可能在案例聲明中)。
2)如果您想將日期/時間轉換為其他時區，則不能使用CultureInfo，
我建議閱讀：[http://msdn.microsoft.com/en-us/library/ms973825.aspx]
您還可以使用.net Framework 3.5類TimeZoneInfo(與TimeZone不同)來簡化生活。
[HTTP://MSDN.Microsoft.com/恩-US/library/system.timezone info.aspx]
hmak answered 2020-07-24T18:24:55Z
0 votes
這是這樣的：
獲取字符串(前提條件：格式：ddd，dd MMM yyyy HH：mm：ss zzz)
獲取最后一個空格
從字符串中刪除zzz，但保存zzz的值
zzz的查詢偏移量
向字符串添加偏移量
string dateString = reader.ReadContentAsString();
int timeZonePos = dateString.LastIndexOf(' ') + 1;
string tz = dateString.Substring(timeZonePos);
dateString = dateString.Substring(0, dateString.Length - tz.Length );
dateString += s_timeZoneOffsets[tz];
// https://msdn.microsoft.com/en-us/library/w2sa9yss(v=vs.110).aspx
//string es = reader.ReadElementString("pubDate");
this.m_value = System.DateTime.ParseExact(dateString, "ddd, dd MMM yyyy HH:mm zzz", System.Globalization.CultureInfo.InvariantCulture);
與
private static System.Collections.Generic.Dictionary s_timeZoneOffsets =
new System.Collections.Generic.Dictionary() {
{"ACDT", "+10:30"},
{"ACST", "+09:30"},
{"ADT", "-03:00"},
{"AEDT", "+11:00"},
{"AEST", "+10:00"},
{"AHDT", "-09:00"},
{"AHST", "-10:00"},
{"AST", "-04:00"},
{"AT", "-02:00"},
{"AWDT", "+09:00"},
{"AWST", "+08:00"},
{"BAT", "+03:00"},
{"BDST", "+02:00"},
{"BET", "-11:00"},
{"BST", "-03:00"},
{"BT", "+03:00"},
{"BZT2", "-03:00"},
{"CADT", "+10:30"},
{"CAST", "+09:30"},
{"CAT", "-10:00"},
{"CCT", "+08:00"},
{"CDT", "-05:00"},
{"CED", "+02:00"},
{"CET", "+01:00"},
{"CEST", "+02:00"},
{"CST", "-06:00"},
{"EAST", "+10:00"},
{"EDT", "-04:00"},
{"EED", "+03:00"},
{"EET", "+02:00"},
{"EEST", "+03:00"},
{"EST", "-05:00"},
{"FST", "+02:00"},
{"FWT", "+01:00"},
{"GMT", "+00:00"},
{"GST", "+10:00"},
{"HDT", "-09:00"},
{"HST", "-10:00"},
{"IDLE", "+12:00"},
{"IDLW", "-12:00"},
{"IST", "+05:30"},
{"IT", "+03:30"},
{"JST", "+09:00"},
{"JT", "+07:00"},
{"MDT", "-06:00"},
{"MED", "+02:00"},
{"MET", "+01:00"},
{"MEST", "+02:00"},
{"MEWT", "+01:00"},
{"MST", "-07:00"},
{"MT", "+08:00"},
{"NDT", "-02:30"},
{"NFT", "-03:30"},
{"NT", "-11:00"},
{"NST", "+06:30"},
{"NZ", "+11:00"},
{"NZST", "+12:00"},
{"NZDT", "+13:00"},
{"NZT", "+12:00"},
{"PDT", "-07:00"},
{"PST", "-08:00"},
{"ROK", "+09:00"},
{"SAD", "+10:00"},
{"SAST", "+09:00"},
{"SAT", "+09:00"},
{"SDT", "+10:00"},
{"SST", "+02:00"},
{"SWT", "+01:00"},
{"USZ3", "+04:00"},
{"USZ4", "+05:00"},
{"USZ5", "+06:00"},
{"USZ6", "+07:00"},
{"UT", "-00:00"},
{"UTC", "-00:00"},
{"UZ10", "+11:00"},
{"WAT", "-01:00"},
{"WET", "-00:00"},
{"WST", "+08:00"},
{"YDT", "-08:00"},
{"YST", "-09:00"},
{"ZP4", "+04:00"},
{"ZP5", "+05:00"},
{"ZP6", "+06:00"}
};
Stefan Steiger answered 2020-07-24T18:25:41Z
-1 votes
這就是我要做的。
我從javascript接收了datetime，然后將其傳遞到ASP.NET以存儲在Oracle數據庫中。 這是我在東部和中部時間的C＃代碼。
string datetimevalue = hidfileDateTime.Value;
datetimevalue= datetimevalue.Replace("EDT", "EST");
datetimevalue = datetimevalue.Replace("CDT", "CST");
if (datetimevalue.Contains("CST"))
{
filedt = DateTime.ParseExact(datetimevalue, "ddd MMM d HH:mm:ss CST yyyy", provider).ToUniversalTime().AddHours(1).ToLocalTime();
}
else
{
filedt = DateTime.ParseExact(datetimevalue, "ddd MMM d HH:mm:ss EST yyyy", provider);
}
Deep Kumar answered 2020-07-24T18:26:05Z
總結
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