這將允許您迭代行。它的一部分是從我在answer中找到的一些代碼派生出來的。

在這個時間點(pylzma-0.5.0)上，py7zlib模塊沒有實現允許存檔成員作為字節流或字符流讀取的API，它的ArchiveFile類只提供一個read()函數，該函數一次解壓縮并返回成員中的未壓縮數據。考慮到這一點，最好的方法是通過Python生成器將字節或行作為緩沖區迭代返回。

下面是后者，但如果問題是存檔成員文件本身太大，則可能沒有幫助。

下面的代碼應該可以在Python3.x和2.7中使用。import io

import os

import py7zlib

class SevenZFileError(py7zlib.ArchiveError):

pass

class SevenZFile(object):

@classmethod

def is_7zfile(cls, filepath):

""" Determine if filepath points to a valid 7z archive. """

is7z = False

fp = None

try:

fp = open(filepath, 'rb')

archive = py7zlib.Archive7z(fp)

_ = len(archive.getnames())

is7z = True

finally:

if fp: fp.close()

return is7z

def __init__(self, filepath):

fp = open(filepath, 'rb')

self.filepath = filepath

self.archive = py7zlib.Archive7z(fp)

def __contains__(self, name):

return name in self.archive.getnames()

def readlines(self, name, newline=''):

r""" Iterator of lines from named archive member.

`newline` controls how line endings are handled.

It can be None, '', '\n', '\r', and '\r\n' and works the same way as it does

in StringIO. Note however that the default value is different and is to enable

universal newlines mode, but line endings are returned untranslated.

"""

archivefile = self.archive.getmember(name)

if not archivefile:

raise SevenZFileError('archive member %r not found in %r' %

(name, self.filepath))

# Decompress entire member and return its contents iteratively.

data = archivefile.read().decode()

for line in io.StringIO(data, newline=newline):

yield line

if __name__ == '__main__':

import csv

if SevenZFile.is_7zfile('testing.csv.7z'):

sevenZfile = SevenZFile('testing.csv.7z')

if 'testing.csv' not in sevenZfile:

print('testing.csv is not a member of testing.csv.7z')

else:

reader = csv.reader(sevenZfile.readlines('testing.csv'))

for row in reader:

print(', '.join(row))

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