我是多線程的新手,我得到了一個問題,使用

Java中的10個線程以低于約束打印1到100.

>線程t1應打印：

1, 11, 21, 31, … 91

t2應打印：

2, 12, 22, 32, … 92

同樣

t10應打印：

10, 20, 30, … 100

>最終的輸出應該是

1 2 3 .. 100

我試過了,但它在所有10個線程中拋出以下異常：

java.lang.IllegalMonitorStateException

at java.lang.Object.wait(Native Method)

at java.lang.Object.wait(Object.java:485)

at thread.run(MyThread.java:58)

at java.lang.Thread.run(Unknown Source)

請讓我知道如何解決這個問題.

public class MyThread {

/**

* @param args

*/

public static void main(String[] args) {

thread.setSequence();

for(int i = 1; i <= 10; i++) {

Thread t = new Thread(new thread(i));

t.setName(i + "");

t.start();

}

}

}

class thread implements Runnable {

private static HashMap< String, String> sequence = new HashMap();

public static final Object lock = new Object();

public static String turn = "1";

private int startValue = 0;

private AtomicInteger counter = new AtomicInteger(1);

public thread(int startValue){

this.startValue = startValue;

}

@Override

public void run() {

while (!counter.equals(10)){

synchronized (lock) {

if(Thread.currentThread().getName().equals(turn)){

System.out.print(startValue + " ");

startValue += 10;

counter.incrementAndGet();

turn = getNextTurn(turn);

try {

this.wait();

} catch (InterruptedException e) {

e.printStackTrace();

}

}

else{

try {

this.wait();

} catch (InterruptedException e) {

e.printStackTrace();

}

}

this.notifyAll();

}

}

}

public static void setSequence(){

for (int i = 1; i <= 10; i++)

if (i == 10)

sequence.put(i + "", 1 + "");

else

sequence.put(i + "", (i + 1) + "");

}

public static String getNextTurn(String currentTurn){

return sequence.get(currentTurn);

}

}

總結

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