? ? 優(yōu)秀的程序猿不僅要有深厚理論基礎,更要有縝密的思維, 一個簡單的函數(shù), 有非常多人都寫不好,為什么,

? ? 不是做不到,不是想不到,? 往往是因為懶而不愿意深入思考.? 有句話叫, 天下大事, 必做于細.

??? int Spline::findTimeInterval(Number time, int startIndex)

??? {
???????? int length = this->_times.size();
???????? if (time < this->_times[0] || time > this->_times[length - 1])
???????? {
????????????? throw? DeveloperError("time is out of range.");
???????? }

???????? if (startIndex < 0 || startIndex > length-1)
???????? {
???????????? throw DeveloperError("length is out of range.");
???????? }

????????? // Take advantage of temporal coherence by checking current, next and previous intervals
????????? // for containment of time.
????????? if (time >= this->_times[startIndex])
????????? {
????????????? if (startIndex + 1 < length && time < this->_times[startIndex + 1])
????????????? {
????????????????? return startIndex;
????????????? }
????????????? else if (startIndex + 2 < length && time < this->_times[startIndex + 2])
????????????? {
????????????????? return startIndex + 1;
????????????? }
????????? }
????????? else if (startIndex - 1 >= 0 && time >= this->_times[startIndex - 1])
????????? {
????????????? return startIndex - 1;
????????? }

????????? // The above failed so do a linear search. For the use cases so far, the
????????? // length of the list is less than 10. In the future, if there is a bottle neck,
????????? // it might be here.

????????? int i;
????????? if (time > this->_times[startIndex])
????????? {
????????????? for (i = startIndex; i < length - 1; ++i) {
????????????????? if (time >= this->_times[i] && time < this->_times[i + 1]) {
????????????????????? break;
????????????????? }
????????????? }
????????? } else {
????????????? for (i = startIndex - 1; i >= 0; --i) {
????????????????? if (time >= this->_times[i] && time < this->_times[i + 1]) {
????????????????????? break;
????????????????? }
????????????? }
????????? }

????????? if (i == length - 1) {
????????????? i = length - 2;
????????? }

????????? return i;
?? ?}

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