更改 pandas dataframe 中兩列的位置：

把其中的某列移到第一列的位置。

原來的 df 是：

df = pd.read_csv('I:/Papers/consumer/codeandpaper/TmallData/result01.csv') Net Upper Lower Mid Zsore Answer option More than once a day 0% 0.22% -0.12% 2 65 Once a day 0% 0.32% -0.19% 3 45 Several times a week 2% 2.45% 1.10% 4 78 Once a week 1% 1.63% -0.40% 6 65

要將? Mid 這一列移動到第一列?

　　　　　　　　　　　　　　　Mid Upper Lower Net Zsore Answer option More than once a day 2 0.22% -0.12% 0% 65 Once a day 3 0.32% -0.19% 0% 45 Several times a week 4 2.45% 1.10% 2% 78 Once a week 6 1.63% -0.40% 1% 65

?

解決辦法：（使用 ix ）

法一：

In [27]: # get a list of columns cols = list(df) # move the column to head of list using index, pop and insert cols.insert(0, cols.pop(cols.index('Mid'))) cols Out[27]: ['Mid', 'Net', 'Upper', 'Lower', 'Zsore'] In [28]: # use ix to reorder df = df.ix[:, cols] df Out[28]:Mid Net Upper Lower Zsore Answer_option More_than_once_a_day 2 0% 0.22% -0.12% 65 Once_a_day 3 0% 0.32% -0.19% 45 Several_times_a_week 4 2% 2.45% 1.10% 78 Once_a_week 6 1% 1.63% -0.40% 65

?

法二：

In [39]: mid = df['Mid'] df.drop(labels=['Mid'], axis=1,inplace = True) df.insert(0, 'Mid', mid) df Out[39]:Mid Net Upper Lower Zsore Answer_option More_than_once_a_day 2 0% 0.22% -0.12% 65 Once_a_day 3 0% 0.32% -0.19% 45 Several_times_a_week 4 2% 2.45% 1.10% 78 Once_a_week 6 1% 1.63% -0.40% 65

?

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#### full data df = pd.read_csv('I:/Papers/consumer/codeandpaper/TmallData/result01.csv') def func(x):return str(x['time_stamp'])+str(x['user_id']) df['session_id'] = df.apply(func, axis=1) del df['time_stamp']sessionID=df['session_id'] df.drop(labels=['session_id'],axis=1,inplace=True) df.insert(0,'session_id',sessionID) df.to_csv('I:/Papers/consumer/codeandpaper/TmallData/result02.csv')

? 最終的處理結果：

?? ?

?

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