1、采用 Array(str)、String(array) 方法

String轉Character數組：Array(str)
Character數組轉String：String(array)

let test = "i like ios" let array = Array(test) //[Character] let string = String(array) //String print(array) print(string)

結果打印：

[“i”, " ", “l”, “i”, “k”, “e”, " ", “i”, “o”, “s”]
i like ios

2、采用String.components(separatedBy: " ")、[String].joined(separator: " ")

String轉[String]數組：String.components(separatedBy: " ")
[String]數組轉String：[String].joined(separator: " ")

let test = "i like ios" let array = test.components(separatedBy: " ")let intArray = [1,2,3,4,5] let dataArray = intArray.map(String.init) let resultString = dataArray.joined(separator: "") print(array) print(resultString)

結果打印：

[“i”, “like”, “ios”]
12345

3、采用String.index(吐槽一下：這api真不好用)

String獲取指定index的Character：String[String.index]
String根據index區間獲取SubString：String(String[index_1...index_2])

let test = "i like ios" let char_0 = test[test.index(test.startIndex, offsetBy: 0)] let char_8 = test[test.index(test.startIndex, offsetBy: 8)] let beginIndex = test.index(test.startIndex, offsetBy: 0) let endIndex = test.index(test.startIndex, offsetBy: 8) let subString = String(test[beginIndex...endIndex]) print(char_0) print(char_8) print(subString)

結果打印：

i
o
i like io

tips:

swift里的字符、字符串處理api比較多，在此記錄幾個經常使用的swift字符相關處理技巧

let charOfA = Character("A") let uInt8Value = charOfA.asciiValue! //Character轉UInt8 let char = Character(UnicodeScalar(uInt8Value)) //UInt8轉Characterlet intArray = [1,2,3,4,5,6] let strArray = intArray.map(String.init) //[Int]轉[String]let str_Array = ["123","01","xx","000"] let int_Array = str_Array.map(Int.init) //[String]轉[Int?] 因為有的字符串無法轉int,該index存在且為nil

總結

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