共回答了15個問題采納率：100%

import java.util.*;

public class Test24 {

public static void main(String[] args) {

int year1, month1, day1;

int num;

Scanner scan = new Scanner(System.in);

MyDate d1, d2;

System.out.println("請輸入一個日期");

System.out.print("年：");

year1 = scan.nextInt();

System.out.print("月：");

month1 = scan.nextInt();

System.out.print("日：");

day1 = scan.nextInt();

try{

d1 = new MyDate(year1, month1, day1);

System.out.println(d1.toString() + " 是一個合法日期");

}

catch(Exception e){

System.out.println(" 非法日期");

}

System.out.println("請輸入一個日期");

System.out.print("年：");

year1 = scan.nextInt();

System.out.print("月：");

month1 = scan.nextInt();

System.out.print("日：");

day1 = scan.nextInt();

System.out.println("時間間隔：");

num = scan.nextInt();

try{

d1 = new MyDate(year1, month1, day1);

d2 = d1.dateAdd(num);

System.out.println(d1.toString() + " 在" + num + "天后就是 " + d2.toString());

}

catch(Exception e){

System.out.println(" 非法日期");

}

try{

d1 = new MyDate(2009, 2, 27);

d2 = new MyDate(2011, 3, 1);

num = d1.dateDiff(d1, d2);

System.out.println(d1.toString() + " ~ " + d2.toString() + " 相隔 " + num + " 天");

}

catch(Exception e){

System.out.println(" 非法日期");

}

}

}

class MyDate{

private int year;

private int month;

private int day;

private int[] days = new int[]{31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

public MyDate(){

}

public MyDate(int year, int month, int day) throws Exception{

if(year < 0 || month12 || daydays[month-1]){

throw new Exception("非法日期");

}

if(month == 2){

if(isLeapYear(year)==true && day>29){

throw new Exception("非法日期");

}

if(isLeapYear(year)==false && day>28){

throw new Exception("非法日期");

}

}

this.year = year;

this.month = month;

this.day = day;

}

//給定一個日期值，計算若干天后的日期值

public MyDate dateAdd(int num) throws Exception{

MyDate d = new MyDate(this.year, this.month, this.day);

days[1] = isLeapYear(d.year) ? 29 : 28;

d.day += num;

if(num > 0){

while(d.day > days[d.month-1]){

d.day -= days[d.month-1];

d.month++;

if(d.month > 12){

d.month = 1;

d.year++;

days[1] = isLeapYear(d.year) ? 29 : 28;

}

}

}

else{

while(d.day

1年前

13

總結

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