日韩性视频-久久久蜜桃-www中文字幕-在线中文字幕av-亚洲欧美一区二区三区四区-撸久久-香蕉视频一区-久久无码精品丰满人妻-国产高潮av-激情福利社-日韩av网址大全-国产精品久久999-日本五十路在线-性欧美在线-久久99精品波多结衣一区-男女午夜免费视频-黑人极品ⅴideos精品欧美棵-人人妻人人澡人人爽精品欧美一区-日韩一区在线看-欧美a级在线免费观看

歡迎訪問 生活随笔!

生活随笔

當(dāng)前位置: 首頁 > 编程资源 > 编程问答 >内容正文

编程问答

CODEFORCES 272C Dima and Staircase 细节理解题+简单技巧

發(fā)布時間:2024/1/8 编程问答 33 豆豆
生活随笔 收集整理的這篇文章主要介紹了 CODEFORCES 272C Dima and Staircase 细节理解题+简单技巧 小編覺得挺不錯的,現(xiàn)在分享給大家,幫大家做個參考.

傳送門:http://codeforces.com/problemset/problem/272/C

C. Dima and Staircase time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output

Dima's got a staircase that consists of?n?stairs. The first stair is at height?a1, the second one is at?a2, the last one is at?an(1?≤?a1?≤?a2?≤?...?≤?an).

Dima decided to play with the staircase, so he is throwing rectangular boxes at the staircase from above. The?i-th box has width?wi?and height?hi. Dima throws each box vertically down on the first?wi?stairs of the staircase, that is, the box covers stairs with numbers1,?2,?...,?wi. Each thrown box flies vertically down until at least one of the two following events happen:

  • the bottom of the box touches the top of a stair;
  • the bottom of the box touches the top of a box, thrown earlier.

We only consider touching of the horizontal sides of stairs and boxes, at that touching with the corners isn't taken into consideration. Specifically, that implies that a box with width?wi?cannot touch the stair number?wi?+?1.

You are given the description of the staircase and the sequence in which Dima threw the boxes at it. For each box, determine how high the bottom of the box after landing will be. Consider a box to fall after the previous one lands.

Input

The first line contains integer?n?(1?≤?n?≤?105)?— the number of stairs in the staircase. The second line contains a non-decreasing sequence, consisting of?n?integers,?a1,?a2,?...,?an?(1?≤?ai?≤?109;?ai?≤?ai?+?1).

The next line contains integer?m?(1?≤?m?≤?105)?— the number of boxes. Each of the following?m?lines contains a pair of integers?wi,?hi(1?≤?wi?≤?n;?1?≤?hi?≤?109)?— the size of the?i-th thrown box.

The numbers in the lines are separated by spaces.

Output

Print?m?integers — for each box the height, where the bottom of the box will be after landing. Print the answers for the boxes in the order, in which the boxes are given in the input.

Please, do not use the?%lld?specifier to read or write 64-bit integers in?C++. It is preferred to use the?cin,?cout?streams or the?%I64dspecifier.

Examples input 5 1 2 3 6 6 4 1 1 3 1 1 1 4 3 output 1 3 4 6 input 3 1 2 3 2 1 1 3 1 output 1 3 input 1 1 5 1 2 1 10 1 10 1 10 1 10 output 1 3 13 23 33 Note

The first sample are shown on the picture.


#include<iostream>using namespace std;long long a[1000000],i,j,n,m,h1,L,h,w; int main() {cin>>n;for (i=1; i<=n; i++)cin>>a[i];cin>>m;for (i=0; i<m; i++){cin>>w>>h;L=max(L+h1,a[w]);cout<<L<<endl;h1=h;}return 0; }

總結(jié)

以上是生活随笔為你收集整理的CODEFORCES 272C Dima and Staircase 细节理解题+简单技巧的全部內(nèi)容,希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網(wǎng)站內(nèi)容還不錯,歡迎將生活随笔推薦給好友。