https://www.luogu.org/problem/show?pid=2871

題目描述

Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

有N件物品和一個容量為V的背包。第i件物品的重量是c[i]，價值是w[i]。求解將哪些物品裝入背包可使這些物品的重量總和不超過背包容量，且價值總和最大。

輸入輸出格式

輸入格式：

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• Line 1: Two space-separated integers: N and M

• Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di

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輸出格式：

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• Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

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輸入輸出樣例

輸入樣例#1：
4 6 1 4 2 6 3 12 2 7 輸出樣例#1：
23


1 #include <algorithm> 2 #include <iostream> 3 #include <cstdio> 4 5 using namespace std; 6 7 int n,m,w[120053],val[120053]; 8 int f[120053]; 9 10 int main() 11 { 12 scanf("%d%d",&n,&m); 13 for(int i=1;i<=n;i++) 14 scanf("%d%d",&w[i],&val[i]); 15 for(int i=1;i<=n;i++) 16 for(int V=m;V>=w[i];V--) 17 f[V]=max(f[V],f[V-w[i]]+val[i]); 18 printf("%d",f[m]); 19 return 0; 20 }

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轉載于:https://www.cnblogs.com/Shy-key/p/6718316.html

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