方法一：

var result = [];

var data = [

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

? {name:'chen',age:'25'},

]

for(var i=0;i<data.length;i+=3){

? ? result.push(data.slice(i,i+3));

}

? //[

//[{name:'chen',age:'25'},{name:'chen',age:'25'},{name:'chen',age:'25'}],

//[{name:'chen',age:'25'},{name:'chen',age:'25'},{name:'chen',age:'25'}],

//[{name:'chen',age:'25'},{name:'chen',age:'25'},{name:'chen',age:'25'}],

//[{name:'chen',age:'25'}],

? //]

方法二：

var spArray = function(N,Q){

var R = [],F;

for (F = 0;F < Q.length;) {

R.push(Q.slice(F,F += N))

}

return R

}

var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14];

console.log(spArray(5,arr))//[[1,2,3,4,5],[6,7,8,9,10],[11,12,13,14]]

原文鏈接：https://blog.csdn.net/qq_43156398/article/details/90715915

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