由于博主太菜，就直接上圖了，結(jié)果是正確的。

1：首先看下數(shù)據(jù)庫(kù)

2：對(duì)應(yīng)的實(shí)體類

3：mapper.xml和mapper.java

再xml中根據(jù)限定條件查詢出當(dāng)前所有的部門集合

4：在serviceImpl中做邏輯處理，最后用遞歸求出結(jié)果。

public class PostTotalNumServiceImpl implements PostTotalNumService {

/**

* 根據(jù)部門ID獲取該部門及其下屬部門的ID集合

*/

public List getDeptIdList(String deptId) {

Department department = this.getDepartment(deptId);

List deptIdList = new ArrayList<>();

if (department != null) {

deptIdList.add(department.getId());

deptIdList = addDeptIdList(deptIdList, department);

}

return deptIdList;

}

/**

* 根據(jù)部門ID獲取該部門及其下屬部門樹

*/

public Department getDepartment(String deptId) {

List departments = departmentMapper.findAllDepartments();

Map map = departments.stream().collect(

Collectors.toMap(Department::getId, department -> department));

for (Department dept : map.values()) {

Department parent = map.get(dept.getPid());

if (parent != null) {

List children = parent.getChildren() == null ? new ArrayList<>() : parent.getChildren();

children.add(dept);

parent.setChildren(children);

}

}

return map.get(deptId);

}

public List addDeptIdList(List deptIdList, Department department) {

List children = department.getChildren();

if (children != null) {

for (Department d : children) {

deptIdList.add(d.getId());

addDeptIdList(deptIdList, d);

}

}

return deptIdList;

}

}

5：service接口

public interface PostTotalNumService {

/**

*查出當(dāng)前部門和下屬部門的集合

*/

List deptList(String pkDept);

}

6：junit單元測(cè)試

public class PostTest extends BaseTest {

@Autowired

private PostTotalNumService postService;

@Test

public void postTest(){

//查詢當(dāng)前部門及下屬部門的集合

List strings = postService.deptList("1001K31000000003M1BT");

System.out.println(strings.size());

}

}

總結(jié)

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