你鏈接的代碼是Joe Kington的numpy包的分支.

您發(fā)布的git clone命令將該fork的源代碼下載到本地計算機(jī).然后你必須編譯numpy并安裝它才能使用這個版本的numpy.

獲取isclose函數(shù)的最簡單方法是將代碼復(fù)制到文件中并導(dǎo)入它：

utils_num.py

import numpy as np

def isclose(a, b, rtol=1.e-5, atol=1.e-8, equal_nan=False):

"""

https://github.com/joferkington/numpy/blob/3a85c0a9af64b0296b9a4c97f43f2f209c849077/numpy/core/numeric.py

Returns a boolean array where two arrays are element-wise equal within a

tolerance.

The tolerance values are positive, typically very small numbers. The

relative difference (`rtol` * abs(`b`)) and the absolute difference

`atol` are added together to compare against the absolute difference

between `a` and `b`.

Parameters

----------

a, b : array_like

Input arrays to compare.

rtol : float

The relative tolerance parameter (see Notes).

atol : float

The absolute tolerance parameter (see Notes).

equal_nan : bool

Whether to compare NaN's as equal. If True, NaN's in `a` will be

considered equal to NaN's in `b` in the output array.

Returns

-------

y : array_like

Returns a boolean array of where `a` and `b` are equal within the

given tolerance. If both `a` and `b` are scalars, returns a single

boolean value.

See Also

--------

allclose

Notes

-----

For finite values, isclose uses the following equation to test whether

two floating point values are equivalent.

absolute(`a` - `b`) <= (`atol` + `rtol` * absolute(`b`))

The above equation is not symmetric in `a` and `b`, so that

`isclose(a, b)` might be different from `isclose(b, a)` in

some rare cases.

Examples

--------

>>> np.isclose([1e10,1e-7], [1.00001e10,1e-8])

array([True, False])

>>> np.isclose([1e10,1e-8], [1.00001e10,1e-9])

array([True, True])

>>> np.isclose([1e10,1e-8], [1.0001e10,1e-9])

array([False, True])

>>> np.isclose([1.0, np.nan], [1.0, np.nan])

array([True, False])

>>> np.isclose([1.0, np.nan], [1.0, np.nan], equal_nan=True)

array([True, True])

"""

def within_tol(x, y, atol, rtol):

result = np.less_equal(abs(x - y), atol + rtol * abs(y))

if np.isscalar(a) and np.isscalar(b):

result = result[0]

return result

x = np.array(a, copy=False, ndmin=1)

y = np.array(b, copy=False, ndmin=1)

xfin = np.isfinite(x)

yfin = np.isfinite(y)

if np.all(xfin) and np.all(yfin):

return within_tol(x, y, atol, rtol)

else:

# Avoid subtraction with infinite/nan values...

cond = np.zeros(broadcast(x, y).shape, dtype=bool)

mask = xfin & yfin

cond[mask] = within_tol(x[mask], y[mask], atol, rtol)

# Check for equality of infinite values...

cond[~mask] = (x[~mask] == y[~mask])

if equal_nan:

# Make NaN == NaN

cond[isnan(x) & isnan(y)] = True

return cond

test.py：

import utils_num as UN

print(UN.isclose([1e10,1e-7], [1.00001e10,1e-8]))

產(chǎn)量

array([ True, False], dtype=bool)

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