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PAT甲级 -- 1041 Be Unique (20 分)

發布時間:2024/2/28 编程问答 36 豆豆
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Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1,10?4??]. The first one who bets on a unique number wins. For example, if there are 7 people betting on { 5 31 5 88 67 88 17 }, then the second one who bets on 31 wins.

Input Specification:

Each input file contains one test case. Each case contains a line which begins with a positive integer?N?(≤10?5??) and then followed by?N?bets. The numbers are separated by a space.

Output Specification:

For each test case, print the winning number in a line. If there is no winner, print?None?instead.

Sample Input 1:

7 5 31 5 88 67 88 17

Sample Output 1:

31

Sample Input 2:

5 888 666 666 888 888

Sample Output 2:

None

AC:

#include <iostream> #include <cmath> #include <vector> using namespace std;int n; struct number {int id, num; }nn; int mx = -1; bool flag = false; int arr[100000+5] = {0}, num; vector<number> v;int main() {scanf("%d", &n);for(int i = 0; i < n; i++){scanf("%d", &num);nn.id = i;nn.num = num;v.push_back(nn);arr[num] += 1;}for(int i = 0; i < v.size(); i++){if(arr[v[i].num] == 1){printf("%d", v[i].num);flag = true;break;}}if(!flag) printf("None");return 0; }

?剛開始打算用數字下標記錄,忽略了順序,后面改為vector,ok了

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