日韩性视频-久久久蜜桃-www中文字幕-在线中文字幕av-亚洲欧美一区二区三区四区-撸久久-香蕉视频一区-久久无码精品丰满人妻-国产高潮av-激情福利社-日韩av网址大全-国产精品久久999-日本五十路在线-性欧美在线-久久99精品波多结衣一区-男女午夜免费视频-黑人极品ⅴideos精品欧美棵-人人妻人人澡人人爽精品欧美一区-日韩一区在线看-欧美a级在线免费观看

歡迎訪問 生活随笔!

生活随笔

當前位置: 首頁 > 编程资源 > 编程问答 >内容正文

编程问答

【openjudge 计算概论(A)】[基础编程练习(运算成分)]

發布時間:2024/3/7 编程问答 50 豆豆
生活随笔 收集整理的這篇文章主要介紹了 【openjudge 计算概论(A)】[基础编程练习(运算成分)] 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

01:雞尾酒療法

#include<cstdio> #include<cstring> #include<algorithm> using namespace std; const double eps=0.05; int n,x,y; int main() {scanf("%d%d%d",&n,&x,&y);double p=(double)y/x;for(int i=1;i<n;++i){int x,y;scanf("%d%d",&x,&y);double sum=(double)y/x;if(sum-p>eps) printf("better\n");else if(p-sum>eps) printf("worse\n");else printf("same\n");}return 0; }

02:求出e的值

#include<cstdio> #include<cstring> #include<algorithm> #define ll long long using namespace std; ll mi[20]; int n; int main() {int i,j;scanf("%d",&n);mi[1]=1;for(i=2;i<=n;++i) mi[i]=mi[i-1]*i;double ans=1;for(i=1;i<=n;++i) ans+=(double)1/mi[i];printf("%.10lf\n",ans);return 0; }

03:球彈跳高度的計算(等比數列)

#include<cstdio> #include<cstring> #include<algorithm> using namespace std; double ans,n; int main() {int i;scanf("%lf",&n);ans=n;i=9;double last=n;while(i--){ans+=n;n/=2; }n/=2;printf("%g %g\n",ans,n);return 0; }

04:求分數序列和

#include<cstdio> using namespace std; double ans,a[1100],b[1100]; int n; int main() {scanf("%d",&n);a[1]=2.0; a[2]=3.0;b[1]=1.0; b[2]=2.0;for(int i=3;i<=n;++i) a[i]=a[i-1]+a[i-2],b[i]=b[i-1]+b[i-2];for(int i=1;i<=n;++i) ans+=(a[i]/b[i]);printf("%.4lf\n",ans);return 0; }

06:角谷猜想

#include<cstdio> #include<cstring> #include<iostream> using namespace std; int x; void pract(int x) {if(x==1){printf("End\n"); return;}if (x%2) {int a=x*3+1; printf("%d*3+1=%d\n",x,a); pract(a);}else {int a=x/2; printf("%d/2=%d\n",x,a); pract(a);}return; } int main() {scanf("%d",&x);pract(x);return 0; }

07:分數求和

#include<cstdio> #include<cstring> #include<algorithm> using namespace std; int fm[20],fz[20],n,lcm,sum; int gcd(int a,int b) {if (!(a%b)) return b;else return gcd(b,a%b); } int main() {int i,j;scanf("%d",&n);for (i=1;i<=n;++i){char c;scanf("%d%c%d",&fz[i],&c,&fm[i]);}lcm=fm[1];for (i=2;i<=n;++i) lcm=lcm*fm[i]/gcd(lcm,fm[i]);for (i=1;i<=n;++i){int sm=fz[i]*(lcm/fm[i]);sum+=sm;}if (!(sum%lcm)) {printf("%d\n",sum/lcm); return 0;}int ans=gcd(lcm,sum);sum/=ans; lcm/=ans;printf("%d/%d",sum,lcm);return 0; }

08:人民幣支付

#include<cstdio> using namespace std; int main() {int n;scanf("%d",&n);printf("%d\n",n/100);n%=100;printf("%d\n",n/50);n%=50;printf("%d\n",n/20);n%=20;printf("%d\n",n/10);n%=10;printf("%d\n",n/5);n%=5;printf("%d\n",n);return 0; }

09:年齡與疾病

#include<cstdio> #include<cstring> #include<algorithm> using namespace std; int age[110]; int n,num[5]; int main() {scanf("%d",&n);for(int i=1;i<=n;++i) {int x;scanf("%d",&x);if(x>=1&&x<=18) num[1]++;if(x>=19&&x<=35) num[2]++;if(x>35&&x<=60) num[3]++;if(x>60) num[4]++;}printf("1-18: %.2lf%%\n",(double)num[1]/(double)n*(100.0));printf("19-35: %.2lf%%\n",(double)num[2]/(double)n*(100.0));printf("36-60: %.2lf%%\n",(double)num[3]/(double)n*(100.0));printf("60-: %.2lf%%\n",(double)num[4]/(double)n*(100.0));return 0; }

10:求特殊自然數

#include<cstdio> #include<cstring> #include<algorithm> using namespace std; int a[5],b[5],opt; inline bool check() {for(int i=1;i<=3;++i)if(a[i]!=b[i]) return 0;return 1; } int main() {int i;scanf("%d",&opt);for(i=81;i<=342;++i){int x=i,y=i;a[1]=x%9; x/=9;a[2]=x%9; x/=9;a[3]=x%9; x/=9;b[3]=y%7; y/=7;b[2]=y%7; y/=7;b[1]=y%7; y/=7;if(check()) break;}if(opt==1) printf("%d\n",i);if(opt==2) printf("%d%d%d\n",b[1],b[2],b[3]);if(opt==3) printf("%d%d%d\n",a[3],a[2],a[1]);return 0; }








轉載于:https://www.cnblogs.com/lris-searching/p/9403025.html

總結

以上是生活随笔為你收集整理的【openjudge 计算概论(A)】[基础编程练习(运算成分)]的全部內容,希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯,歡迎將生活随笔推薦給好友。