近期的開發(fā)工作中，遇到一個需求。一組時間段內(nèi)，取出連續(xù)的時間段分組。

如2016-01-01,2016-01-02,2016-01-03，2016-01-04,2016-01-06，2016-01-07
結(jié)果為[2016-01-01,2016-01-03],[2016-01-04,2016-01-04],[2016-01-06,2016-01-07]。

廢話不多說，上代碼。注意需要先對list進行小到大排序。

List<Map<String,Object>> object = new ArrayList<Map<String,Object>>(); //測試數(shù)據(jù)Map<String,Object> map = new HashMap<String,Object>(); map.put("scheduleDate", "2017-12-11");object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-12");object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-13");object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-14"); //1object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-16"); //2object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-18"); object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-19");object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-20");//3object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-22");object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-23");object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-24"); //4object.add(map);map = new HashMap<String,Object>();map.put("scheduleDate", "2017-12-28"); //5object.add(map);Date startDate = dateFormat.parse(object.get(0).get("scheduleDate").toString());Date endDate = null;boolean is = false; List<Map<String,Object>> tempList= new ArrayList<Map<String,Object>>();for (int i = 0; i < object.size(); i++) {if(is){startDate = dateFormat.parse(object.get(i).get("scheduleDate").toString());is = false;}Date parse = dateFormat.parse(object.get(i).get("scheduleDate").toString());Date parseNext = null;if((i+1)==object.size()){parseNext = dateFormat.parse(object.get(i).get("scheduleDate").toString());}else{parseNext = dateFormat.parse(object.get(i+1).get("scheduleDate").toString());}calendar.setTime(parse);calendar.add(Calendar.DATE, 1);Date time2 = calendar.getTime();//如果parse+1天不等于parse1if (parseNext .compareTo(time2)!=0 || (i+1)==object.size()) { if ((i+1)==object.size()) { //如果循環(huán)到最后一個endDate=parseNext;}else{endDate=parse;}Map<String,Object> map1 = new HashMap<String,Object>();map1.put("begin", dateFormat.format(startDate));map1.put("end", dateFormat.format(endDate));tempList.add(map1);startDate = parseNext ;is = true;}}

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