統計條數

String[] countArr = new String[23];//mapper層代碼List<Map<String, Object>> selectData(@Param("countArr")String[] countArr);

查詢當天24小時 sql 語句?

SELECTcount( u.id ) AS `value`,s.date AS textFROM(SELECTdate_add( DATE_FORMAT( CURDATE( ), '%Y-%m-%d %H:%i:%s' ), INTERVAL @i := @i + 1 HOUR ) AS dateFROM( SELECT 1<foreach item = "index" collection = "countArr" >UNION ALL SELECT 1</foreach>) AS tmp,( SELECT @i := - 1 ) t) sLEFT JOIN lsd_order u ON HOUR ( s.date ) = HOUR ( u.create_time )GROUP BYs.date

結果:

2.時間段內顯示每一天

int date = calcBetweenDate(startTime, endTime);String[] countArr = new String[date];

?calcBetweenDate 計算天數

public int calcBetweenDate(String start, String end) {SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd");Date startDate = null;Date endDate = null;try {startDate = df.parse(start);endDate = df.parse(end);} catch (Exception e) {log.error("時間轉換問題:"+e);}int count = (int) ((endDate.getTime() - startDate.getTime()) / (24 * 60 * 60 * 1000));return count;}

mapper層

List<Map<String, Object>> selectData(@Param("startTime")String startTime,@Param("countArr")String[] countArr);

sql 語句

SELECTcount( u.id ) AS value,s.date AS textFROM(SELECTdate_add(#{startTime}, INTERVAL @i := @i + 1 DAY) AS dateFROM( SELECT 1<foreach item = "index" collection = "countArr" >UNION ALL SELECT 1</foreach>) AS tmp,( SELECT @i := - 1 ) t) sLEFT JOIN lsd_order u ON s.date = date_format(u.create_time,'%Y-%m-%d')GROUP BYs.date

?

總結

以上是生活随笔為你收集整理的sql语句查询一天24小时每个小时数据，查询时间段内每天数据的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。