To find the limit of x^2 + 3 as x approaches 2, we can simply substitute x = 2 into the expression x^2 + 3. lim(x→2) (x^2 + 3) = 2^2 + 3 = 4 + 3 = 7 Therefore, lim(x→2) (x^2 + 3) = 7.

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