[select * from city t order by t.city_id]

如上圖中數(shù)據(jù)顯示的那樣，現(xiàn)在要求 city_id 此表中不連接的的ID號。

0 ~ 11 之間丟失的數(shù)據(jù)是?? 1 ~ 10????????????????丟失數(shù)量 10

15 ~ 21 之間丟失的數(shù)據(jù)是 16 ~ 20????????????????丟失數(shù)量??5

....?????????????????????????????????????????????????????????? ....

顯示出來的內容應該是

lost_id????????????????????????????????lost_sum

1~10,16~20?????????????????????? 15

最后如下圖所示：

現(xiàn)在使用sql 顯示上面的信息 select wm_concat(preced_id||'~'||last_id)lose_id,sum(last_id -preced_id + 1 ) lose_sum from ( ??select p_id +1 preced_id,c_id -1 last_id,a.city_name from ( ????select ??????first_value(t.city_id)over(order by t.city_id rows between 1 preceding and 1 following) p_id ,--上一個ID的值 ??????t.city_id c_id,?????????????????????????????????????????????????????????????????????????????? --當前的ID值 ??????last_value(t.city_id)over(order by t.city_id rows between 1 preceding and 1 following )n_id,??--后一個ID的值 ??????t.city_parent_id,t.city_name ????from city t ????--where t.city_id < 100 ??) a ??where a.p_id + 1 <> a.c_id and c_id -1 > 0 ) 在上面的SQL語句中 first_value(field) 函數(shù)，哪一列的值 over(order by t.city_id rows between 1 preceding and 1 following)??是 field 列當中當前行的 前一行的以后一行。 first_value(t.city_id)over(order by t.city_id rows between 1 preceding and 1 following) 是獲取city_id列當前行的前一行的值。 last_value(t.city_id)over(order by t.city_id rows between 1 preceding and 1 following ) 獲取當city_id列當前行的下一行的值。

總結

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