動態淀粉質即可

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#include "rts.h" #include<algorithm> #include<unordered_map> #include<cstdlib> #include<ctime> #include<map> const int maxn = 300300; int per[maxn],vis[maxn]; typedef long long ll; std::map<int,int> ans[maxn]; int N; inline int get(int x,int y){return explore(x,y); } namespace list{const int LEFT=1,RIGHT=0;inline void solve(int to,int&l,int&r,int type=LEFT){if(l==to||r==to)return ;if(type == LEFT){int p=get(l,to);if(vis[p])solve(to,l,r,RIGHT);else vis[p]=1,solve(to,l=p,r,type);}else{int p=get(r,to);vis[p]=1,solve(to,l,r=p,type);}} } namespace wwj{int n;const double alpha=0.6;struct sol_tree{int size,rt;std::map<int,sol_tree*> son;inline sol_tree(int p){size=1,rt=p;}inline ~ sol_tree(){son.clear();}};struct T{int to,nxt;}way[maxn<<1];int h[maxn],num;inline void adde(int x,int y){way[++num]={y,h[x]},h[x]=num;way[++num]={x,h[y]},h[y]=num;}inline void up(int&x,int y){if(x<y)x=y;}sol_tree ** rebd;int vis[maxn];namespace dfz{int vis[maxn],size[maxn];inline void init(){for(int i=1;i<=n;++i)vis[i]=1;}inline void getsz(int x){vis[x]=size[x]=1;for(int i=h[x];i;i=way[i].nxt)if(!vis[way[i].to])getsz(way[i].to),size[x]+=size[way[i].to];vis[x]=0;}int rt,v;inline void getrt(int x,int al){vis[x]=1;int ms=0;for(int i=h[x];i;i=way[i].nxt)if(!vis[way[i].to])getrt(way[i].to,al),up(ms,size[way[i].to]);if(std::max(al-size[x],ms)<v)v=std::max(al-size[x],ms),rt=x;vis[x]=0;}inline int getroot(int x){getsz(x),v=1e9,getrt(x,size[x]);return rt;}inline sol_tree* sol(int x){x=getroot(x),vis[x]=1;sol_tree * ret = new sol_tree(x);for(int i=h[x];i;i=way[i].nxt)if(!vis[way[i].to]){sol_tree * tmp=ret->son[way[i].to]=sol(way[i].to);ret->size+=tmp->size;}return ret;}inline void dfscls(sol_tree * rt){vis[rt->rt] = 0;for(std::pair<int,sol_tree*>i:rt->son)dfscls(i.second);delete rt;}}int cnt,sumsz;inline void rebuild(sol_tree ** rebd){++cnt;sol_tree* & rt = * rebd;int R = rt -> rt;sumsz+=rt->size;dfz::dfscls(rt);rt=dfz::sol(R);}inline int ins(sol_tree*&rt,int to){int p = get(rt -> rt,to);if(!vis[p]){sol_tree*&tmp=rt -> son[p] = new sol_tree(p);adde(rt -> rt,p),vis[p]=1;int res=0;if(p!=to)rt->size+=res=ins(tmp,to);if(rt -> size * alpha + 1 < tmp -> size)rebd =&rt;return res+1;}else{sol_tree*&tmp=rt->son[p];int res=0;rt->size+=res=ins(tmp,to);if(rt -> size * alpha + 1 < tmp -> size)rebd =&rt;return res;}}inline void solve(){srand(time(0));for(int i=1;i<=n;++i)per[i]=i;for(int i=1;i<=2;++i)std::random_shuffle(per+1,per+n+1);dfz::init();vis[1]=1;sol_tree * rt = new sol_tree(1);int cnt=n-1;while(cnt){int i=rand()%n+1;if(!vis[per[i]]){rebd=0;cnt-=ins(rt,per[i]);if(rebd)rebuild(rebd);}}} } void play(int n, int T, int dataType){N=wwj::n=n;if(dataType == 3){srand(time(0));for(int i=1;i<=n;++i)per[i]=i;for(int i=1;i<=10;++i)std::random_shuffle(per+1,per+n+1);vis[1]=1;for(int i=1,l=1,r=1;i<=n;++i)if(!vis[per[i]])list::solve(per[i],l,r);}else{wwj::solve();} }

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轉載于:https://www.cnblogs.com/skip1978/p/10342923.html

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