https://leetcode.com/problems/3sum-closest/

題目：

Given an array?S?of?n?integers, find three integers in?S?such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

For example, given array S = {-1 2 1 -4}, and target = 1.The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

思路：

和上一道差不多，主要還是有序數組里兩個flag移動。

AC代碼：

class Solution { public:int threeSumClosest(vector<int>& nums, int target) {int res,t,j,k,lowerbound=INT_MAX,n=nums.size();sort(nums.begin(),nums.end());for(int i=0;i<n-2;i++){t=target-nums[i];j=i+1;k=n-1;while(j<k){if(abs(nums[j]+nums[k]-t)<lowerbound){res=nums[i]+nums[j]+nums[k];lowerbound=abs(nums[j]+nums[k]-t);}if(nums[j]+nums[k]<t)j++;elsek--;}}return res;} };

?

轉載于:https://www.cnblogs.com/aezero/p/4841692.html

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