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LeetCode 190. Reverse Bits (算32次即可)
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LeetCode 190. Reverse Bits (算32次即可)
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題目:
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
代碼:
class Solution { public:uint32_t reverseBits(uint32_t n) {uint32_t x = 0;int t = 32;while(t--){x = x*2+n%2;n /= 2;}return x;} };總結(jié)
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