python输出字典的前十项,从字典列表中获取前5个值?
我從api密鑰獲取json。
這是我的json:{'[{"count":27,"stem":"obama","term":"obama"},
{"count":20,"stem":"boehner","term":"boehner"},
{"count":4,"stem":"tax","term":"tax"},
{"count":3,"stem":"daley","term":"daley"},
{"count":3,"stem":"couldn","term":"couldn"},
{"count":2,"stem":"formul","term":"formulation"}
]' : ' '}
我想從這個json中得到前5個值。我把這個翻到字典列表:
^{pr2}$
所有代碼如下:import urllib2, mediacloud, json,itertools,ast
from collections import Counter
webUrl = urllib2.urlopen("https://api.mediacloud.org/api/v2/wc/list?q=obama+AND+media_id:1&stats=1&&fq=publish_date:%5B2012-04-01T00:00:00.000Z+TO+2012-04-01T00:00:00.000Z%5D&key= ")
def changetodict(data):
json_str = ast.literal_eval(json.dumps(data))
#common = json.loads(json_str)
commonDict = dict(itertools.izip_longest(*[iter(json_str)] * 2, fillvalue=""))
print commonDict
most_common_imdb_value = Counter(b['key'] for b in commonDict).most_common(1)[0]
if(webUrl.getcode()== 200):
data = webUrl.readlines()
changetodict(data)
else:
print "error"
我需要做些什么才能讓它生效?在
總結
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