用LEFT JOIN 代替NOT IN?或 NOT EXISTS：

SQL> conn scott/tiger

Connected.

SQL> CREATE TABLE testa

2? (

3?? id number,

4?? value varchar2(10)

5? );

Table created.

SQL> INSERT INTO testa VALUES(1,'a');

1 row created.

SQL> INSERT INTO testa VALUES(2,'b');

1 row created.

SQL> INSERT INTO testa VALUES(3,'c');

1 row created.

SQL> INSERT INTO testa VALUES(4,'d');

1 row created.

SQL> INSERT INTO testa VALUES(5,'e');

1 row created.

SQL> INSERT INTO testa VALUES(6,'f');

1 row created.

SQL> COMMIT;

Commit complete.

SQL> CREATE TABLE testb AS

2? SELECT * FROM testa WHERE 1=0;

Table created.

SQL> INSERT INTO testb VALUES(2,'b');

1 row created.

SQL> INSERT INTO testb VALUES(4,'d');

1 row created.

SQL> INSERT INTO testb VALUES(6,'f');

1 row created.

SQL> COMMIT;

Commit complete.

用左連接，結果testb表里TempColum的值為NULL：

SQL> SELECT a.*,b.id "TempColum" FROM testa a LEFT JOIN testb b ON a.id=b.id;

ID?? VALUE?????? TempColum

---------- ----------?????? ----------

2?????? b?????????????????? 2

4???? ? d?????????????????? 4

6???? ? f??????????????????? 6

5????? ?e???????????????????NULL

3?????? c?????????????????? NULL

1?????? a???????????????????NULL

6 rows selected.

將NULL值過濾出來就是最后需要的結果：

SQL>

SELECT c.id,c.value FROM

(

SELECT a.*,b.id "TempColum" FROM testa a LEFT JOIN testb b ON a.id=b.id

) c

WHERE c."TempColum" IS NULL

ORDER BY c.id

SQL>

ID VALUE

---------- ----------

1 a

3 c

5 e

總結

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