java url authority,Java如何解析url,包括自定义schema的url
比如我要解析下面這個url:
myscheme://admin@blog.nihao001.com:8080/index.jsp?username=asdf&password=123456&msg=%e4%bd%a0%e5%a5%bd#editor
只要使用URI這個類就可以解析了。
上代碼:
import java.net.URI;
import java.net.URISyntaxException;
public class Main {
public static void main(String[] args) {
String SCHEMA ="myscheme://admin@blog.nihao001.com:8080/index.jsp?username=asdf&password=123456&msg=%e4%bd%a0%e5%a5%bd#editor";
try {
URI uri = new URI(SCHEMA);
System.out.println("getScheme:" + uri.getScheme());
System.out.println("getHost:" + uri.getHost());
System.out.println("getPort:" + uri.getPort());
System.out.println("getAuthority:" + uri.getAuthority());
System.out.println("getPath:" + uri.getPath());
System.out.println("getRawQuery:" + uri.getRawQuery());
System.out.println("getQuery:" + uri.getQuery());
System.out.println("getFragment:" + uri.getFragment());
System.out.println("getRawUserInfo:" + uri.getRawUserInfo());
System.out.println("getUserInfo:" + uri.getUserInfo());
} catch (URISyntaxException e) {
e.printStackTrace();
}
}
}
看結果:
getScheme:myscheme
getHost:blog.nihao001.com
getPort:8080
getAuthority:admin@blog.nihao001.com:8080
getPath:/index.jsp
getRawQueryusername=asdf&password=123456&msg=%e4%bd%a0%e5%a5%bd
getQuery:username=asdf&password=123456&msg=你好
getFragment:editor
getRawUserInfo:admin
getUserInfo:admin
總結
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