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的確很奇怪。我試驗了10幾分鐘，你按下面的方法來做就可以正確。import?struct

zzz?=?("{Type:2}").encode("utf-8")

length?=?len(zzz)

a?=?struct.pack("%ds"%length,zzz)

print(a)

簡單的說32313133353236313431303231363533e59b9ee7ad9431333335326138s其實只是一個字符，所以前面要加一個數字，比如8s，就可以存貯一個長度為8的字符串。你只寫一個s當然只存貯一個。

python幫助的原文如下

For the 's' format

character, the count is interpreted as the size of the string, not a repeat

count like for the other format characters; for example, '10s' means a single

10-byte string, while '10c' means 10 characters. If a count is not given, it

defaults to 1. For packing, the string is truncated or padded with null bytes as

appropriate to make it fit. For unpacking, the resulting string always has

exactly the specified number of bytes. As a special case, '0s' means a single, empty

string (while '0c'

means 0 characters).

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