我在我的一個實時網絡應用程序中遇到了這個問題.看來如果你通過PHP PDO向MysqL發出一個多語句查詢,并且第一個語句是一個insert語句,而第二個語句是一個update語句,那么PDO :: nextRowset()函數不會返回正確的數字結果集(請注意,自PHP 5.3起,PDO應該支持每個MySQL查詢的多個語句.)

這是一個例子：

create database `test`character set utf8 collate utf8_general_ci;

create table `test`.`testtable`( `id` int );

PHP

$link = new \PDO('MysqL:host=localhost;dbname=test','username','password');

//Run one of the 4 $handle assignments at a time (comment out all but one).

//Run #4 on an empty table to compare the results of #1 and #4.

//WORKS: INSERT,followed by SELECT,followed UPDATE

//Output:

//Rowset 1

//Rowset 2

//Results detected

$handle = $link->prepare(' insert into testtable(id) values(1);

select * from testtable where id = ?;

update testtable set id = 2 where id = ?;');

//WORKS: SELECT,followed by UPDATE

//Output:

//Rowset 1

//Results detected

$handle = $link->prepare('select * from testtable where id = ?;

update testtable set id = 2 where id = ?;');

//WORKS: UPDATE,followed by SELECT

//Output:

//Rowset 1

//Rowset 2

//Results detected

$handle = $link->prepare('select * from testtable where id = ?;

update testtable set id = 2 where id = ?;');

//DOESN'T WORK: INSERT,followed by UPDATE,followed by SELECT

//Output:

//Rowset 1

//Expected output: same as examples 1 and 3

$handle = $link->prepare('insert into testtable(id) values(1);

update testtable set id = 2 where id = ?;

select * from testtable where id = ?;');

$handle->bindValue('1','1');

$handle->bindValue('2','2');

$handle->execute();

$i = 1;

do{

print('Rowset ' . $i++ . "\n");

if($handle->columnCount() > 0)

print("Results detected\n");

}while($handle->nextRowset());

?>

有沒有人知道我做錯了什么？為什么我不能把我的選擇聲明放在最后？

PHP 5.3.5

MysqL 5.1.54

總結

以上是生活随笔為你收集整理的pdo 错误 php,多语句查询中的PHP PDO错误的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。