Java黑皮書課后題第9章：**9.12（幾何：交點）假設兩條線段相交。第一條線段的兩個端點是（x1, y1）和（x2, y2），第二條線段的兩個端點是（x3, y3）和（x4, y4）

• 題目
• • 破題
• 代碼
• • Test12
  • Test11_LinearEquation
  • 運行結果

題目

點擊這里跳轉編程練習題3.25
點擊這里跳轉編程練習題9.11

破題

Test12：測試程序
Test11_LinearEquation：實現題目要求（本身題目已經要求使用9.11的LinearEquation類解決

代碼

Test12

import java.util.Scanner;public class Test12 {public static void main(String[] args) {// 獲取用戶輸入的四個點System.out.println("請輸入四個點的坐標值");Scanner input = new Scanner(System.in);double x1 = input.nextDouble(), y1 = input.nextDouble();double x2 = input.nextDouble(), y2 = input.nextDouble();double x3 = input.nextDouble(), y3 = input.nextDouble();double x4 = input.nextDouble(), y4 = input.nextDouble();// 求a b c d e fdouble a = - (y2 - y1) / (x2 - x1);double b = 1.0, d = 1.0;double c = - (y4 - y3) / (x4 -x3);double e = a * x1 + y1;double f = c * x3 + y3;// 傳入數值Test11_LinearEquation le = new Test11_LinearEquation(a, b, c, d, e, f);// 判斷是否有結果boolean bool = le.isSolvable();if (bool){System.out.println("x is " + le.getX() + " and y is " + le.getY());} elseSystem.out.println("The equation has no solution");} }

Test11_LinearEquation

public class Test11_LinearEquation {private double a, b, c, d, e, f;// 構造方法public Test11_LinearEquation (double a, double b, double c, double d, double e, double f){this.a = a;this.b = b;this.c = c;this.d = d;this.e = e;this.f = f;}// getterpublic double getA() {return a;}public double getB() {return b;}public double getC() {return c;}public double getD() {return d;}public double getE() {return e;}public double getF() {return f;}// isSolvable方法public boolean isSolvable(){boolean bool = false;if (a * d - b * c != 0){bool = true;}return bool;}// getX和getYpublic double getX(){return (e * d - b * f) / (a * d - b * c);}public double getY(){return (a * f - e * c) / (a * d - b * c);} }

運行結果

請輸入四個點的坐標值 1 1 2 2 3 3 4 4 The equation has no solution

總結

以上是生活随笔為你收集整理的Java黑皮书课后题第9章：**9.12（几何：交点）假设两条线段相交。第一条线段的两个端点是(x1, y1)和(x2, y2)，第二条线段的两个端点是(x3, y3)和(x4, y4)的全部內容，希望文章能夠幫你解決所遇到的問題。

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