我正在開發一個下拉菜單，該菜單使用HTML optgroups作為員工所屬的組名。這是MySQL查詢和輸出：

mysql> SELECT employee.emp_id，employees.empname，employees.grp_id，groups.groupname FROM雇員離開的雇員加入員工組。grp_id= groups.grp_id，按組名asc排序；

+ -------- + ------------ + -------- + ----------- +

| emp_id | empname | grp_id | 組名|

+ -------- + ------------ + -------- + ----------- +

| 20 | 員工2 | 13 | 第1組|

| 19 | 員工1 | 13 | 第1組|

| 21 | 員工3 | 14 | 第2組|

+ -------- + ------------ + -------- + ----------- +

設置3行(0.00秒)

唯一的問題是，我很難確定如何使optgroup正常工作。我嘗試了無數次，這真的開始讓我感到沮喪。 以下是我想要的輸出示例(示例)：

Employee 2

Employee 1

Employee 3

基本上，optgroup必須是“ groupname”，選項“ name”應該是“ emp_id”，而動作“ option”(下拉項)是“

empname”。

我希望這是可以做的，但是真的不確定。這是我所擁有的功能，但無法正常運行：

function getDynGrpList() {

global $db;

// $query = "SELECT * FROM employees ORDER BY grp_id desc;";

$query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;";

$employees = $db->GetAll($query);

$groups = array();

while ($qa = $employees->GetRows()) {

$groups[$qa['groupname']][$qa['grp_id']] = $qa['empname'];

}

foreach ($groups as $label => $opt) { ?>

foreach ($groups[$label] as $id => $name) { ?>

從凌晨3:15 CST(2/27)開始的getDynGrpList函數：

function getDynGrpList() {

global $db;

// $query = "SELECT * FROM employees ORDER BY grp_id desc;";

$query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;";

$employees = $db->GetAll($query);

$groups = array();

while ($qa = $employees->GetRows()) {

$groups[$qa['groupname']][$qa['emp_id']] = $qa['empname'];

}

var_export($groups);

foreach($groups as $label => $opt): ?>

<?php foreach ($opt as $id => $name): ?>

}

最終解決方案(在Felix Kling的幫助下)

function getDynGrpList() {

global $db;

$query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;";

$employees = $db->GetAll($query);

$groups = array();

foreach ($employees as $employee) {

$groups[$employee['groupname']][$employee['emp_id']] = $employee['empname'];

}

foreach($groups as $label => $opt): ?>

<?php foreach ($opt as $id => $name): ?>

}

總結

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