這似乎對我有用。在r = re.compile(ur'[^\x09\x0A\x0D\x20-\x7E\x85\xA0-\xFF' \

+ ur'\u0100-\uD7FF\uE000-\uFDCF\uFDE0-\uFFFD]')

def escapeInvalidXML(string):

def replacer(m):

return ""+('%04X' % ord(m.group(0)))+""

return re.sub(r,replacer,string)

示例：

^{pr2}$

更新：哎呀，忘了適應SAX的startElement/characters方法，正確處理多行代碼：import re

import xml.sax.xmlreader

import xml.sax.saxutils

r = re.compile(ur'(.*?)(?:([^\x09\x0A\x0D\x20-\x7E\x85\xA0-\xFF' \

+ ur'\u0100-\uD7FF\uE000-\uFDCF\uFDE0-\uFFFD])|([\n])|$)')

attr0 = xml.sax.xmlreader.AttributesImpl({})

def splitInvalidXML(string):

list = []

def replacer(m):

g1 = m.group(1)

if (len(g1) > 0):

list.append(g1)

g2 = m.group(2)

if (not g2 == None):

list.append(ord(g2))

g3 = m.group(3)

if (not g3 == None):

list.append(g3)

return ""

re.sub(r,replacer,string)

return list

def submitCharacters(x, string):

for fragment in splitInvalidXML(string):

if (isinstance(fragment,int)):

x.startElement("u", attr0)

x.characters('%04X' % fragment)

x.endElement("u")

else:

x.characters(fragment)

def test1(fname):

with open(fname,'w') as f:

x = xml.sax.saxutils.XMLGenerator(f)

x.startDocument()

x.startElement('document',attr0)

submitCharacters(x, 'this is a \x01 test\nof the \x02\x0b xml system.')

x.endElement('document')

x.endDocument()

test1('test.xml')

這會產生：<?xml version="1.0" encoding="iso-8859-1"?>

this is a 0001 test

of the 0002000B xml system.

總結

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