The given expression can be written as: (-1)^2 + (2)^2 + (-3)^2 + (4)^2 + (-5)^2 + ... + (n)^2 Simplifying each term, we get: 1 + 4 + 9 + 16 + 25 + ... + (n)^2 The sum of squares from 1^2 to n^2 can be calculated using the formula for the sum of consecutive square numbers: Sum = n * (n + 1) * (2n + 1) / 6 So, the sum of the given expression is: Sum = n * (n + 1) * (2n + 1) / 6

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