我正試圖在我的

java窗口上移動一列火車并遇到嚴重問題.我有一個火車課,我在那里制作了火車,還有一個駕駛課,它應該可以移動火車.我需要讓整列火車從右向左移動,直到它“通過”屏幕的左邊緣.然后添加一個if語句來更改dx,以便列車在右側重新啟動.以下是我嘗試過的但是沒有用.有人可以幫我嗎？

public class Driver extends GraphicsProgram

{

//~ Instance/static variables .............................................

private static final int N_STEPS = 1000;

private static final int PAUSE_TIME = 20;

private static final double TRAIN_LENGTH = 320;

//~ Constructor ...........................................................

// ----------------------------------------------------------

/**

* The run() method of the Driver Class.

* Creates an instance of the Train Class.

* Responsible for animating the train across the screen.

*/

public void run()

{

Train train = new Train(getGCanvas());

for (int i = 0; i < N_STEPS; i++) {

train.move(-100, 0);

pause(PAUSE_TIME);

}

最佳答案 這是一個用搖擺做的小演示.只需用火車圖像替換黑色矩形就可以了.

訣竅是使用單獨的線程(或計時器)來進行動畫循環(通常稱為游戲循環).循環僅告訴窗口重繪自己,并且在每次重繪時,首先計算動畫對象的新位置,然后繪制它們.

import javax.swing.*;

import java.awt.*;

public class TrainDemo {

public static void main(String[] args) {

JFrame frame = new JFrame("Train Demo");

frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

frame.setSize(800, 400);

frame.setLocationRelativeTo(null);

frame.add(new TrainCanvas());

frame.setVisible(true);

}

}

class TrainCanvas extends JComponent {

private int lastX = 0;

public TrainCanvas() {

Thread animationThread = new Thread(new Runnable() {

public void run() {

while (true) {

repaint();

try {Thread.sleep(10);} catch (Exception ex) {}

}

}

});

animationThread.start();

}

public void paintComponent(Graphics g) {

Graphics2D gg = (Graphics2D) g;

int w = getWidth();

int h = getHeight();

int trainW = 100;

int trainH = 10;

int trainSpeed = 3;

int x = lastX + trainSpeed;

if (x > w + trainW) {

x = -trainW;

}

gg.setColor(Color.BLACK);

gg.fillRect(x, h/2 + trainH, trainW, trainH);

lastX = x;

}

}

總結

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